Answer:
A)0.00022s b)40363.6N c) 0.025m/s
Explanation:
Mass = 24g = 0.024kg, distance though the target = thickness of the target = 25cm = 0.25m
Initial speed of the bullet = 1300m/s, final speed = 930m/s
Using equation of motion
Distance = 1/2(vf+vi)*t (time in seconds)
t = 0.25*2/(1300+930) = 0.00022s
B) force exerted on the body
F = ma = m* (vf-vi)/t = 0.024*(930-1300)/0.00022
F = -40363N, it is negative because the body decelerated during this motion
C) using law of conservation of momentum,
M1*U1+ M2*U2(M2and U1 are the mass and initial speed of the body) = M1V1+ M2V2
The target was at rest so initial speed U2 = 0
0.024*1300 + 360*0 = 0.024*930 + 360*V2
31.2 = 22.32+360*V2
31.2-22.33 = 360*V2
V2 = 8.88/360 = 0.025m/s
Answer:
Explanation:
1 ) the volume of helium in the balloon when fully inflated
= 4/3 π R³
= 4/3 x 3.14 x 5.3³
= 623.3 m³
2 ) force of gravity on the entire system ,but with no people
= (mass of the empty balloon and basket + mass of helium )x g
=( 129 + 623.3 x.18 )x 9.8
= 2363.7 N
3 ) magnitude of the buoyant force on the entire system (but with no people )
( Volume of empty balloon + basket + volume of helium ) density of air x g
( 0.057 + 623.3 ) x 1.23 x 9.8
= 7513.94 N
4 ) magnitude of the force of gravity on each person
Mass of each person x g
= 71 x 9.8
= 695.8 N
