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lord [1]
3 years ago
10

Jupiter is 317 times more massive than the Earth. Its gravitational attraction is _____ Earth's.

Physics
2 answers:
NeTakaya3 years ago
6 0
That all depends on your distance from the center of each planet.

On the surface of Jupiter, the acceleration of gravity is 2.53 times
its value on the surface of the Earth.
ElenaW [278]3 years ago
3 0

Answer: Jupiter gravitational attraction is stronger than the Earth's gravitation attraction. Correct answer is option(3).

Explanation:

Force of gravitational attraction of the Earth on object with mass m at distance r from its center.

F_e=G\frac{M_em}{r^2}

Force of gravitational attraction of the Jupiter on object with mass m at distance r from its center.

F_j=G\frac{M_jm}{r^2}

M_j=317\times M_e (given)

F_j=G\frac{317\times M_em}{r^2}=317\times F_e

The gravitation force exerted by Jupiter will be 317 times of the gravitation force exerted by planet earth.

Hence, Jupiter gravitational attraction is stronger than the Earth's gravitation attraction.

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a 40-kg mass rest at the edge of a board that is 2 meters long. the coefficients of friction are .80 and .40. the board is slowl
DanielleElmas [232]
At about 38.6598 degrees
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3 0
4 years ago
Find the pressure necessary to change a volume of steel by
kramer

Answer:

160×10⁶ bar

Explanation:

Bulk modulus is defined as:

K = -V ΔP / ΔV

where V is the initial volume,

ΔP is the change in pressure,

and ΔV is the change in volume.

Given:

K = 160×10⁹ Pa

ΔV = -0.01V

160×10⁹ Pa = -V ΔP / (-0.01V)

160×10⁹ Pa = ΔP / 0.01

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3 0
3 years ago
What statement applies to the horizontal rows or periods in the periodic table? A. The properties are all the same. B. The eleme
Sliva [168]
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7 0
3 years ago
In the illustration above the moon is in the position called
larisa [96]

Answer: new moon I think

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8 0
3 years ago
Read 2 more answers
A 6.80 $\mu C$ particle moves through a region of space where an electric field of magnitude 1230 N/C points in the positive $x$
Murljashka [212]

Answer:

v = -227.785 m/s

Explanation:

The electric field exerts the following force on the electric particle:

F = qE

F = 6.65 \times 10^{-6} \times 1230

F = 0.0081795 \ N

The magnetic field exerts the following force on the particle::

F = qvB

F = 6.65\times 10^{-6} \times v \times 1.32

F = 8.778 \times 10^{-6} \times v

Total force acting is:

F = qvB + qE

6.18 \times 10^{-3} = 0.0081795 + 8.778 \times 10^{-6} \times v

v = \dfrac{6.18 \times 10^{-3}  -0.0081795 }{8.778 \times 10^{-6}}

v = -227.785 m/s

5 0
3 years ago
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