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lord [1]
3 years ago
10

Jupiter is 317 times more massive than the Earth. Its gravitational attraction is _____ Earth's.

Physics
2 answers:
NeTakaya3 years ago
6 0
That all depends on your distance from the center of each planet.

On the surface of Jupiter, the acceleration of gravity is 2.53 times
its value on the surface of the Earth.
ElenaW [278]3 years ago
3 0

Answer: Jupiter gravitational attraction is stronger than the Earth's gravitation attraction. Correct answer is option(3).

Explanation:

Force of gravitational attraction of the Earth on object with mass m at distance r from its center.

F_e=G\frac{M_em}{r^2}

Force of gravitational attraction of the Jupiter on object with mass m at distance r from its center.

F_j=G\frac{M_jm}{r^2}

M_j=317\times M_e (given)

F_j=G\frac{317\times M_em}{r^2}=317\times F_e

The gravitation force exerted by Jupiter will be 317 times of the gravitation force exerted by planet earth.

Hence, Jupiter gravitational attraction is stronger than the Earth's gravitation attraction.

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A hamster of mass 0.139 kg gets onto his 20.8−cm-diameter exercise wheel and runs along inside the wheel for 0.823 s until its f
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Explanation:

Given that,

Mass of the hamster, m = 0.139 kg

Diameter of the wheel, d = 20.8 cm

Radius, r = 10.4 m

Frequency of the wheel, f = 1 Hz

Time, t = 0.823 s

(a) There exist a relationship between the tangential and angular acceleration of the wheel. It is given by :

a=\alpha \times r

Since, \alpha =\dfrac{\omega}{t}

a=\dfrac{\omega}{t} \times r

a=\dfrac{2\pi f}{t} \times r

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(b) In radial direction, applying the second law of motion as :

N-mg=ma

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N=mg+ma

N=mg+m(\dfrac{v^2}{r})

N=mg+m(\dfrac{(r\omega)^2}{r})

N=mg+m\omega^2 r

N=m(g+\omega^2 r)

N=m(g+(2\pi f)^2 r)

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8 0
4 years ago
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Answer:

c.holding a sign in the air

Explanation:

because b is kinetic energy and a is also kinetic energy

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