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Nonamiya [84]
3 years ago
5

A highway curves to the left with radius of curvature of 36 m and is banked at 28 ◦ so that cars can take this curve at higher s

peeds. Consider a car of mass 1717 kg whose tires have a static friction coefficient 0.87 against the pavement. top view R = 36 m 28 ◦ rear view µ = 0.87 How fast can the car take this curve without skidding to the outside of the curve? The acceleration of gravity is 9.8 m/s 2 . Answer in units of m/s.
Physics
1 answer:
iVinArrow [24]3 years ago
5 0

Answer: 30.34m/s

Explanation:

The sum of forces in the y direction 0 = N cos 28 - μN sin28 - mg

Sum of forces in the x direction

mv²/r = N sin 28 + μN cos 28

mv²/r = N(sin 28 + μcos 28)

Thus,

mv²/r = mg [(sin 28 + μ cos 28)/(cos 28 - μ sin 28)]

v²/r = g [(sin 28 + μ cos 28)/(cos 28 - μ sin 28)]

v²/36 = 9.8 [(0.4695 + 0.87*0.8829) - (0.8829 - 0.87*0.4695)]

v²/36 = 9.8 [(0.4695 + 0.7681) / (0.8829 - 0.4085)]

v²/36 = 9.8 (1.2376/0.4744)

v²/36 = 9.8 * 2.6088

v²/36 = 25.57

v² = 920.52

v = 30.34m/s

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From conservation of energy, the height he will reach when he has gravitational potential energy 250J is 0.42 meters approximately

The given weight of Elliot is 600 N

From conservation of energy, the total mechanical energy of Elliot must have been converted to elastic potential energy. Then, the elastic potential energy from the spring was later converted to maximum potential energy P.E of Elliot.

P.E = mgh

where mg = Weight = 600

To find the height Elliot will reach, substitute all necessary parameters into the equation above.

250 = 600h

Make h the subject of the formula

h = 250/600

h = 0.4167 meters

Therefore, the height he will reach when he has gravitational potential energy 250J is 0.42 meters approximately

Learn more about energy here: brainly.com/question/24116470

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Which object has the most gravitational potential energy?
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Answer: An 8 kg book at a height of 3 m has the most gravitational potential energy.

Explanation:

Gravitational potential energy is the product of mass of object, height of object and gravitational field.

So, formula to calculate gravitational potential energy is as follows.

U = mgh

where,

m = mass of object

g = gravitational field = 9.81 m/s^{2}

h = height of object

(A) m = 5 kg and h = 2m

Therefore, its gravitational potential energy is calculated as follows.

U = mgh\\= 5 kg \times 9.81 m/s^{2} \times 2 m\\= 98.1 J    (1 J = kg m^{2}/s^{2})

(B) m = 8 kg and h = 2 m

Therefore, its gravitational potential energy is calculated as follows.

U = mgh\\= 8 kg \times 9.81 m/s^{2} \times 2 m\\= 156.96 J    (1 J = kg m^{2}/s^{2})

(C) m = 8 kg and h = 3 m

Therefore, its gravitational potential energy is calculated as follows.

U = mgh\\= 8 kg \times 9.81 m/s^{2} \times 3 m\\= 235.44 J    (1 J = kg m^{2}/s^{2})

(D) m = 5 kg and h = 3 m

Therefore, its gravitational potential energy is calculated as follows.

U = mgh\\= 5 kg \times 9.81 m/s^{2} \times 3 m\\= 147.15 J    (1 J = kg m^{2}/s^{2})

Thus, we can conclude that an 8 kg book at a height of 3 m has the most gravitational potential energy.

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3 years ago
Geologists use tools other than the law of superposition to help them with relative dating. Which statements describe those tool
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Answer: Cross-cutting features are always younger than the surrounding rock.

When material erodes before sediment is deposited on it, a geologic gap results.

Explanation:

The options include:

1. An unconformity is created when lava pours out on Earth’s surface.

2. Faults are the result of volcanic activity.

3. Intrusions and extrusions are sedimentary formations.

4. Cross-cutting features are always younger than the surrounding rock.

5. When material erodes before sediment is deposited on it, a geologic gap results.

The law of superposition simply states that when there is a layers of rocks, we would see that the younger layers will lie and be on top of the layers that are older.

Other tools that can help scientist with relative dating are:

• Cross-cutting features are always younger than the surrounding rock.

• When material erodes before sediment is deposited on it, a geologic gap results.

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