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3 years ago

I NEED THIS ANSWER TODAY PLEASE HELP ME

2 answers:

7 0

The answer is "B" - If there are no windows then there will be no light coming in, and therefore you don't have to worry about what time of day you do the experiment at.

Inessa05 [86]3 years ago

5 0

B. The time of day

^^ not really sure but haha

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A cart is pushed on a frictionless floor with 29.6 Newtons of force along a distance of 5.9 meters in 8.1 seconds. How much powe

marta [7]

Answer:

Power = 21.6 Watts

Explanation:

Power = $\frac{W}{t}$

Where W = work and t = time.

W = Fs

Where F is force and s is displacement.

29.6N(5.9m) = 174.64J

W = 174.64J

Power = $\frac{174.64J}{8.1s}$

Power = 21.6 Watts

8 0

3 years ago

I NEED HELP, PLEASE.

Zinaida [17]

Hello,

I'd be glad to help.

Momentum = (mass) times (speed)

= (75 kg) x (18 m/s)

= 1,350 kg-m/s .

Hope this helps

5 0

3 years ago

How much work would be needed to raise the payload from the surface of the moon (i.e., x = r) to the "end of the universe"?

meriva

Moon was rotation Earth or sun
it's own orbit . universe is not end

6 0

3 years ago

Read 2 more answers

A mass weighing 4 lb stretches a spring 2 in. Suppose that the mass is given an additional 6-in displacement in the positive dir

givi [52]

Answer:

$\frac{1}{8} y'' + 2y' + 24y=0$

Explanation:

The standard form of the 2nd order differential equation governing the motion of mass-spring system is given by

$my'' + \zeta y' + ky=0$

Where m is the mass, ζ is the damping constant, and k is the spring constant.

The spring constant k can be found by

$w - kL=0$

$mg - kL=0$

$4 - k\frac{1}{6}=0$

$k = 4\times 6 =24$

The damping constant can be found by

$F = -\zeta y'$

$6 = 3\zeta$

$\zeta = \frac{6}{3} = 2$

Finally, the mass m can be found by

$w = 4$

$mg=4$

$m = \frac{4}{g}$

Where g is approximately 32 ft/s²

$m = \frac{4}{32} = \frac{1}{8}$

Therefore, the required differential equation is

$my'' + \zeta y' + ky=0$

$\frac{1}{8} y'' + 2y' + 24y=0$

The initial position is

$y(0) = \frac{1}{2}$

The initial velocity is

$y'(0) = 0$

6 0

3 years ago

A car with an initial velocity of 5.0 is acelerated at 3.0for 4.0seconds what os the velocity of tje car ofter the 4.0seconds

sasho [114]

Vf =Vi+at
Vf= 5 + 3*4
Vf=5+12
Vf=17m/sec

6 0

3 years ago