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Rus_ich [418]
3 years ago
14

Find the pressure necessary to change a volume of steel by

Physics
1 answer:
kramer3 years ago
3 0

Answer:

160×10⁶ bar

Explanation:

Bulk modulus is defined as:

K = -V ΔP / ΔV

where V is the initial volume,

ΔP is the change in pressure,

and ΔV is the change in volume.

Given:

K = 160×10⁹ Pa

ΔV = -0.01V

160×10⁹ Pa = -V ΔP / (-0.01V)

160×10⁹ Pa = ΔP / 0.01

ΔP = 160×10¹¹ Pa

ΔP = 160×10⁶ bar

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A bus travels north on some busy city streets for 2.5 km, and a trip
d1i1m1o1n [39]

Answer:

V = 4.63 m/s

V = 11.31 m/s

Explanation:

Given,

The distance traveled by the bus, towards north, d = 2.5 km

                                                                                     = 2500 m

The time taken by the trip is, t = 9 min

                                                  = 540 s

The velocity of the bus,

                                       V = d / t

                                           = 2500 / 540

                                          = 4.63 m/s

At another  point, the bus travels at a constant speed of v = 18 m/s

Therefore the velocity becomes

                                                V = (4.63 + 18)/2

                                                   = 11.31 m/s

Hence, the velocity of the  bus, V = 11.31 m/s

8 0
3 years ago
The pressure in an automobile tire depends on the temperature of the air in the tire. When the air temperature is 25°C, the pres
12345 [234]

Answer:0.0704 kg

Explanation:

Given

initial Absolute pressure(P_1)=210+101.325=311.325

T_1=25^{\circ}\approx 298 K

V=0.025 m^3

T_2=50^{\circ}\approx 323 K

as the volume remains constant therefore

\frac{P_1}{T_1}=\frac{P_2}{T_2}

\frac{311.325}{298}=\frac{P_2}{323}

P_2=337.44 KPa

therefore Gauge pressure is 337.44-101.325=236.117 KPa

Initial mass m_1=\frac{P_1V}{RT_1}=\frac{311.325\times 0.025}{0.0287\times 298}

m_1=0.91 kg

Final mass m_2=\frac{P_2V}{RT_2}=\frac{311.325\times 0.025}{0.0287\times 323}

m_2=0.839

Therefore m_1-m_2=0.91-0.839=0.0704 kg of air needs to be removed to get initial pressure back

4 0
3 years ago
An object has a weight of 500 on earth what is the mass of this object
erastova [34]

550! OBVY! lol! ope this helps1

7 0
4 years ago
Samantha is checking the weather for her upcoming trip to Mexico City. The weather forecast predicts a high-pressure system for
Zanzabum

Calm, sunny days with wind moving away from the center.

5 0
3 years ago
Read 2 more answers
You push a desk with 245 N, but the desk doesn't move due to its friction with the ground. What is the magnitude of the friction
const2013 [10]

If the desk doesn't move, then it's not accelerating.

If it's not accelerating, then the net force on it is zero.

If the net force on it is zero, then any forces on it are balanced.

If there are only two forces on it and they're balanced, then they have equal strengths, and they point in opposite directions.

So the friction on the desk must be equal to your<em> 245N</em> .

7 0
3 years ago
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