Answer:
For any collision occurring in an isolated system, momentum is conserved. The total amount of momentum of the collection of objects in the system is the same before the collision as after the collision.
Explanation:
Hope this helps
Answer:
The fraction of its energy that it radiates every second is
.
Explanation:
Suppose Electromagnetic radiation is emitted by accelerating charges. The rate at which energy is emitted from an accelerating charge that has charge q and acceleration a is given by

Given that,
Kinetic energy = 6.2 MeV
Radius = 0.500 m
We need to calculate the acceleration
Using formula of acceleration

Put the value into the formula

Put the value into the formula


We need to calculate the rate at which it emits energy because of its acceleration is

Put the value into the formula


The energy in ev/s


We need to calculate the fraction of its energy that it radiates every second


Hence, The fraction of its energy that it radiates every second is
.
Answer:
speed is the gradient of the graph
Answer:
36.125 J
Explanation:
The formula for kinetic energy is KE = .5(m)(v²).
Using the given information, mass = 1 g and v = 8.50. Plug that information into the equation. KE = .5(1)(8.50²) = 36.125 J.
Answer:
Density is directly proportional to pressure
Explanation:
As pressure increases (with constant temperature), density also increases.
Density is inversely proportional to temperature.