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CaHeK987 [17]
3 years ago
12

Why is it correct to say seawater is a mixture.

Chemistry
2 answers:
ZanzabumX [31]3 years ago
7 0
It's a mixture of H2O + a soluble substance like, salt.
liq [111]3 years ago
5 0

Answer:

It's a mixture of H2O + a soluble substance like, salt.

Explanation:

You might be interested in
Which element could provide one atom to make an ionic bond with chlorine
wlad13 [49]
I think the one element that could provide one atom to making an ionic bond will be Sodium 

3 0
4 years ago
If a substance cannot be broken down chemically into a simpler substance what is it
Vikentia [17]

Answer: An Element

Explanation:

An element is a substance that cannot be split into smaller substance. It is made up of one kind of atom and can exist either as molecules  (e.g nitogen) or an atom (e.g argon).

6 0
4 years ago
Read 2 more answers
Match the element with its oxidation number (charge).
Angelina_Jolie [31]

Answer:

The answer is in the problem

Explanation:

As general rule of number of oxygen is -2:

O → -2

Alkali metals (Li, Na, K) are always +1

Na → +1

Alkali earth methals (Be, Mg, Ca...) are always +2

Ca → +2

The halogen group (F, Cl, Br...) is always -1

F → -1

The oxidation number of Si (+/- 4)

Aluminium is, usually +3

And to complete the octet rule in nitrogen, 3 electrons are required. That means:

N → -3

8 0
3 years ago
If 6.0g of carbon is heated in air the mass of the product obtained could be either 22.0g or 14.0g depending on the amount of ai
Gnom [1K]

In accordance with Dalton's Law of multiple proportions

<h3>Further explanation</h3>

Given

6.0g of carbon

22.0g or 14.0g of product

Required

related laws

Solution

the amount of air present ⇒ as an excess or limiting reactant

  • air(O₂) as a limiting reactant(product=14 g)

C+0.5O₂⇒CO

6 + 8 = 14 g

mol O₂=8 g : 32 g/mol=0.25

mol C = 6 g : 12 g/mol = 0.5(2 x mol O₂)

mol CO= 2 x mol O₂ = 0.5 mol = 0.5 x 28 g/mol = 14 g

  • air(O₂) as an excess reactant(product=22 g) an C as a limiting reactant

C+O₂⇒CO₂

6 + 16 = 22 g

mol C = 6 g : 12 g/mol = 0.5

mol O₂ = 16 g : 32 g/mol=0.5

mol CO₂ = 22 g : 44 g/mol = 0.5

if the mass firs element (C) constant, then the mass of the second element(O) in the two compounds will have a ratio as a simple integer.

CO = 6 : 8

CO₂ = 6 : 16

the ratio O = 8 : 16 = 1 : 2

In accordance with Dalton's Law of multiple proportions

4 0
3 years ago
ASAP WILL GET BRAINLIEST IF CORRECT!!!!!!!!!!!!!!!!
tigry1 [53]

Answer:

Both have infinite range i believe

Explanation:

7 0
3 years ago
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