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tia_tia [17]
3 years ago
6

Which of the following pairs have the same specific heat?

Chemistry
1 answer:
WITCHER [35]3 years ago
3 0
I am pretty sure the answer would be the first  one which is 1g of solid lead and 10 g of solid lead. Specific heat is an intensive property which means it is a property that is independent with the amount so for the same substance no matter how much you have this value is the same.
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How many grams are in 2.5 moles of N2? <br><br> (2 decimal places)
Leokris [45]

Answer: How many grams are in 2.5 moles of N2?

Explanation: 1 mole is equal to 1 moles N2, or 28.0134 grams.

 One mole of N2 molecules would have a mass of 2 X 14.01 g = 28.02 g.

3 0
3 years ago
Pls help why is it reduced
Ipatiy [6.2K]

Answer:

its orginal charge is none then through the reaction it is reduced because then final charge is -1 meaning is went down 1 so its charge was reduced

Hope this helps! :)

4 0
2 years ago
Read 2 more answers
Manganese(iv) oxide reacts with aluminum to form elemental manganese and aluminum oxide: 3mno2+4al→3mn+2al2o3part awhat mass of
Oxana [17]
<span>12.4 g First, calculate the molar masses by looking up the atomic weights of all involved elements. Atomic weight manganese = 54.938044 Atomic weight oxygen = 15.999 Atomic weight aluminium = 26.981539 Molar mass MnO2 = 54.938044 + 2 * 15.999 = 86.936044 g/mol Now determine the number of moles of MnO2 we have 30.0 g / 86.936044 g/mol = 0.345081265 mol Looking at the balanced equation 3MnO2+4Al→3Mn+2Al2O3 it's obvious that for every 3 moles of MnO2, it takes 4 moles of Al. So 0.345081265 mol / 3 * 4 = 0.460108353 mol So we need 0.460108353 moles of Al to perform the reaction. Now multiply by the atomic weight of aluminum. 0.460108353 mol * 26.981539 g/mol = 12.41443146 g Finally, round to 3 significant figures, giving 12.4 g</span>
7 0
3 years ago
In the laboratory, a volume of 100 mL of sulfuric acid (H2SO4) is recorded. How many g are there of the liquid if its density is
ser-zykov [4K]

Answer:

\large \boxed{\text{183 g}}  

Explanation:

\begin{array}{rcl}\text{Density} & = & \dfrac{\text{Mass}}{\text{Volume}}\\\\\rho & = &\dfrac{m}{V}\\\\1.83 \text{ g$\cdot$ cm}^{-3} & = & \dfrac{m}{\text{100 cm}^{3}}\\\\m & = & \text{183 g}\\\end{array}\\\text{There are $\large \boxed{\textbf{183 g}}$ of sulfuric acid.}

8 0
3 years ago
Please give me solved answer pic its really importen ​
inn [45]
Where’s the picture?
5 0
3 years ago
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