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Llana [10]
3 years ago
5

1) Find (10) in the sequence given by b(n) = -5+9(n - 1). b(10) =

Mathematics
1 answer:
S_A_V [24]3 years ago
8 0

Answer:

b(10) = 76

Step-by-step explanation:

To find b(10) substitute n = 10 into the formula

b(10) = - 5 + 9(10 - 1) = - 5 + 9(9) = - 5 + 81 = 76

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I rlly need the answer to this thanks
mariarad [96]
The answer is -0.34. hope this helps
5 0
3 years ago
Read 2 more answers
If a = -10/5 then a =... <br><br><br> Please help ASAP!
Sladkaya [172]

Answer:

-2   hope this helps!   :)

Step-by-step explanation:

-10 over 5 is -2

so a = -2

7 0
3 years ago
The population of a pigeons in a city is 100 and is growing exponentially at 20% per year. Write a function to represent the pop
NikAS [45]

Answer:

  • p(t) = 100×1.0153^(12t)
  • 1.53% per month

Step-by-step explanation:

In general, the function will be written ...

  p(t) = (initial value)×(growth factor)^t

where t is in units comparable to those applicable to the growth factor. The growth factor is found from ...

  growth factor = 1 + growth rate

Here, the growth rate is given as 20% per year, so the growth factor per year is ...

  1 +20% = 1.20

The initial value is given as 100, so we can write the exponential function as ...

  p(t) = 100×1.20^t

__

The time period units for t are supposed to be years, but we want to find the growth rate for a month. We can do that by recognizing there are 12 months in a year. In the above equation, we can use (1/12)(12t) in place of t, then figure the growth factor (and growth rate) per month.

  p(t) = 100×(1.20^(1/12))^( 12t)

  p(t) = 100×1.0153^(12t) . . . . population exponential function

This shows the monthly growth factor is 1.0153, so the monthly rate of change (growth rate) is ...

  1.0153 -1 = 0.0153 = 1.53% . . . . monthly rate of change

5 0
2 years ago
Read 2 more answers
Would anyone know how to do this
butalik [34]
Your answer will be 5xplus10
8 0
3 years ago
Rafael must choose a number between 67 and 113 that is a multiple of, 2,4, and 5 . Write all the numbers that he could choose.
skelet666 [1.2K]
First, find out what the greatest common factor is between 2, 4, and 5. 

<span>This is 20. So any number divisible by 20 is also divisible by 2, 4, and 5. </span>

<span>Now we find the list of numbers that are multiples of 20 between 67 and 113. </span>

<span>The solutions are: </span>

<span>80 and 100.</span>
5 0
3 years ago
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