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Anni [7]
2 years ago
11

Please tell me answer ​

Mathematics
1 answer:
Katena32 [7]2 years ago
7 0
I’ll be glad to help :)

(a) <

(b) <

(c) >

(d) <

(e) >

Hope this helps! Have a wonderful day :)
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Can someone help me not sure how to do it
tatyana61 [14]
First add the perimeter
3.65m + 2.24m + 2.24m + 3.65m + 2.57m = 14.35 m
then convert meters to centimeters (just move the decimal place two places to the right) 
answer is 1,435 cm

6 0
3 years ago
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Convert this fraction to a decimal 1/200​
ohaa [14]

Answer:

0.005

Step-by-step explanation:

7 0
2 years ago
Solve for x <br><br><br><br><br><br>.problem down below ​
AleksAgata [21]
A: no solution!

first, simplify each side of the equation.

3x + 5 - 10x simplifies to -7x + 5.
8 - 7x - 12 simplifies to -7x - 4.

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5 0
3 years ago
Lengths of full-term babies in the US are Normally distributed with a mean length of 20.5 inches and a standard deviation of 0.9
mash [69]

Answer:

66.48% of full-term babies are between 19 and 21 inches long at birth

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean length of 20.5 inches and a standard deviation of 0.90 inches.

This means that \mu = 20.5, \sigma = 0.9

What percentage of full-term babies are between 19 and 21 inches long at birth?

The proportion is the p-value of Z when X = 21 subtracted by the p-value of Z when X = 19. Then

X = 21

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.5}{0.9}

Z = 0.56

Z = 0.56 has a p-value of 0.7123

X = 19

Z = \frac{X - \mu}{\sigma}

Z = \frac{19 - 20.5}{0.9}

Z = -1.67

Z = -1.67 has a p-value of 0.0475

0.7123 - 0.0475 = 0.6648

0.6648*100% = 66.48%

66.48% of full-term babies are between 19 and 21 inches long at birth

5 0
2 years ago
Patrick already has 1 plant in his backyard, and he can also grow 1 plant with every seed packet he uses. With 40 seed packets,
sveticcg [70]
41 seed packets you do the math
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3 years ago
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