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Liono4ka [1.6K]

2 years ago

8

A group of students wants to determine the favorite snack food at their school. They know they should use a sample because the s

tudent population at their high school is 5,000. What is the best way for them to get a random sample of 100 students?

1 answer:

e-lub [12.9K]2 years ago

7 0

To create a survey and hand them out to different students

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Joshua orders some drinks for himself and some friends. He orders three cappuccinos, two iced teas, two cafe lattes, and an espr

Tju [1.3M]

Answer: 1.23

Explanation: hope this helps

8 0

3 years ago

All the numbers between 20 and 40 which are multiples of 2 and 3

nydimaria [60]

Answer:

21, 24, 27, 30, 33, 36, 39.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

How do i solve this question

frozen [14]

$\bf \begin{cases}
h(x)=(f\circ g)(x)\\
h(x)=\sqrt{x+5}\\
f(x)=\sqrt{x+2}
\end{cases}\\\\
-------------------------------\\\\
(f\circ g)(x)\implies f[\ g(x)\ ]\implies f[\ g(x)\ ]=\sqrt{g(x)+2}\qquad thus
\\\\\\
\sqrt{g(x)+2}=(f\circ g)(x)=h(x)=\sqrt{x+5}\qquad therefore
\\\\\\
\sqrt{g(x)+2}=\sqrt{x+5}\impliedby \textit{squaring both sides}\\\\\\
g(x)+2=x+5\implies g(x)=x+5-2\implies \boxed{g(x)=x+3}$

8 0

3 years ago

Which of these systems of equations would be best solved using the subtraction method?

Lynna [10]

Answer:

Step-by-step explanation:

1. x+2y=6 or x=6-2y

3x-2y=2

3(6-2y)-2y=2

18-6y-2y=2

18-8y=2

-8y=-18+2

-8y=-16

y=-16/-8

y=2 ans.

x+2*2=6

x+4=6

x=6-4=2 ans.

Proof:

3*2-2*2=2

6-4=2

2=2

I leave the rest for you to practice with.

3. 4x+y=7

2x+5y=-1

5. 3x+2y=-2

6x-y=6

Solve the system using the elimination method. Show all your steps.

7. -3x+3y=3

3x+y=9 add.

---------------------------------

4y=12

y=12/4

y=3 ans.

3x+3=9

3x=9-3

3x=6

x=6/3

x=2 ans.

Proof:

-3*2+3*3=3

-6+9=3

3=3

I'll leave the rest for practice.

9. -5x+12y=20

x-2y=-6

11. 3x+2y=1

4x+ 6y= 7

4 0

2 years ago

Solve the system of equations:

Simora [160]

Answer:

x1=6 , x2=1

Step-by-step explanation:

If you have any questions about the way I solved it,don't hesitate to ask

8 0

3 years ago