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2 years ago

Albert is traveling 50 mph in his car. After 3 hours, how far will he have traveled?

Mathematics

2 answers:

Anarel [89]2 years ago

8 0

Answer:

150 miles

Step-by-step explanation:

We know that:

Albert = 50 m/h
Speed = Distance/Time

Solution:

Albert speed = 50 m/h
=> x/3 = 50
=> x = 50 × 3
=> x = 150

Hence, Albert has traveled 150 miles after 3 hours.

MrMuchimi2 years ago

4 0

The answer would be 150

To solve this do 50x30 and you would get 150

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Ulleksa [173]

Answer:

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Step-by-step explanation:

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3 years ago

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insurance company checks police records on 559 accidents selected at random and notes that teenagers were at the wheel in 91 of

ss7ja [257]

Answer: $(13.22\%,\ 19.34\%)$

Step-by-step explanation:

Given : Sample space : n= 559

Sample proportion : $\hat{p}=\dfrac{91}{559}=0.162790697674\approx0.1628$

$=16.28\%$

Significance level : $\alpha= 1-0.95=0.05$

Critical value : $z_{\alpha/2}=1.96$

Confidence level for population proportion:-

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.1628\pm (1.96)\sqrt{\dfrac{0.1628(1-0.1628)}{559}}\\\\=0.1628\pm0.030604971367\\\\\approx 0.1628\pm0.0306=(0.1322,\ 0.1934)=(13.22\%,\ 19.34\%)$

Hence, 95% confidence interval for the percentage of all auto accidents that involve teenage drivers.= $(13.22\%,\ 19.34\%)$

7 0

3 years ago

Deductions this Week: Federal Tax $52.02, FICA $33.02, State $5.33. Find the annual Federal Tax deduction

Leya [2.2K]

Answer:

The annual federal tax deduction is $2705.04 .

Step-by-step explanation:

As given deduction in a week

Federal Tax $52.02

As there are 52 weeks in a week.

Thus

Annual Federal Tax deduction = Total number of weeks in a year × Federal Tax deduction in week

= 52 × 52.02

= $ 2705.04

Therefore the annual federal tax deduction is $2705.04 .

3 0

3 years ago

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Assume that the heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If

vesna_86 [32]

Answer:

<h2>The probability is 58 %.</h2>

Step-by-step explanation:

This problem belong to a normal distribution probability.

Mean = 63.6

Standard Deviation = 2.5.

We have to find the probability of a height greater than 63.0.

Due to the normal probability, we need to find the Z score first:

$Z=\frac{x-u}{o}$ ; where x is the height, u is the mean, and o is the standard deviation.

$Z=\frac{63-63.6}{2.5} \\Z= -0.24$

Once we have our Z score, we find the probability with the z-table (attached). So, for a z score of -0.24 we have a probability of 0.42.

But, the problem is asking for height greater than 63.0, this mean that we have to subtract 0.42 from 1, giving as result 0.58, which means a 58% of probability,

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4 years ago

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Korolek [52]

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3 years ago

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