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dolphi86 [110]
3 years ago
15

The Graduate Record Examinations are widely used to help predict the performance of applicants to graduate schools. The range of

possible scores on a GRE is 200 to 900. The psychology department at a university finds that the scores of its applicants on the quantitative GRE are approximately normal with mean = 544 and standard deviation = 103. Use your calculator or computer to find the relative frequency of applicants whose score X satisfies the following conditions: (As part of your answer, draw a standard normal curve and shade the area under the curve that represented the answer to the question; do this on scratch paper and provide a one-sentence description for the assignment).
X < 500
Mathematics
1 answer:
Montano1993 [528]3 years ago
5 0
Its X<500 because it states it
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In a scale model of a table, 1 centimeter represents 8 inches.
Trava [24]

Answer:

(a): 6 centimeters

(b): 72 inches

Step-by-step explanation:

Rule: From centimeters to inches, multiply centimeters × 8

so from inches to centimeters, divide inches by 8

Scale:

1 cm : 8 in

? cm : 48 in

6 cm : 48 in

Scale:

? in : 9 cm

72 in : 9 cm

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Scale Drawings question
Nimfa-mama [501]

Answer:

138 is the answer

Step-by-step explanation:

In order to find the perimeter, we use this formula

P=2(l+w)

And to find the width, we use this formula

w = P/2 - L = 18/2 - 3 = 6

So the width is 6

3 × 6 = 18

So thats why the perimeter of the top triangle is 18

We do 21 ÷ 3 = 7, 7 = scale factor

To find the perimeter of the bottom triangle, we do

the width of the top rectangle times 7

so 6 × 7 = 48

So the perimeter for the bottom triangle is

P=2(l+w)=2·(48+21)=138

6 0
3 years ago
Let f be the function defined by f(x) = e^(x) cos x.
Pavel [41]
(a)

The average rate of change of f on the interval 0 ≤ x ≤ π is

   \displaystyle&#10;f_{avg\Delta} = \frac{f(\pi) - f(0)}{\pi - 0} =\frac{-e^\pi-1}{\pi}

____________

(b)

f(x) = e^{x} cos x \implies f'(x) = e^x \cos(x) - e^x \sin(x) \implies \\ \\&#10;f'\left(\frac{3\pi}{2} \right) = e^{3\pi/2} \cos(3\pi/2) - e^{3\pi/2} \sin(3\pi/2) \\ \\&#10;f'\left(\frac{3\pi}{2} \right) = 0 - e^{3\pi/2} (-1) = e^{3\pi/2}

The slope of the tangent line is e^{3\pi/2}.

____________

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The absolute minimum value of f occurs at a critical point where f'(x) = 0 or at endpoints.

Solving f'(x) = 0

f'(x) = e^x \cos(x) - e^x \sin(x) \\ \\&#10;0 = e^x \big( \cos(x) - \sin(x)\big)

Use zero factor property to solve.

e^x \ \textgreater \  0\forall x \in \mathbb{R} so that factor will not generate solutions.
Set cos(x) - sin(x) = 0

\cos (x) - \sin (x) = 0 \\&#10;\cos(x) = \sin(x)

cos(x) = 0 when x = π/2, 3π/2, but x = π/2. 3π/2 are not solutions to the equation. Therefore, we are justified in dividing both sides by cos(x) to make tan(x):

\displaystyle\cos(x) = \sin(x) \implies 0 = \frac{\sin (x)}{\cos(x)} \implies 0 = \tan(x) \implies \\ \\&#10;x = \pi/4,\ 5\pi/4\ \forall\ x \in [0, 2\pi]

We check the values of f at the end points and these two critical numbers.

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\displaystyle f(\pi/4) = e^{\pi/4} \cos(\pi/4) = e^{\pi/4}  \frac{\sqrt{2}}{2}

\displaystyle f(5\pi/4) = e^{5\pi/4} \cos(5\pi/4) = e^{5\pi/4}  \frac{-\sqrt{2}}{2} = -e^{\pi/4}  \frac{\sqrt{2}}{2}

f(2\pi) = e^{2\pi} \cos(2\pi) = e^{2\pi}

There is only one negative number.
The absolute minimum value of f <span>on the interval 0 ≤ x ≤ 2π is
-e^{5\pi/4} \sqrt{2}/2

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(d)

The function f is a continuous function as it is a product of two continuous functions. Therefore, \lim_{x \to \pi/2} f(x) = f(\pi/2) = e^{\pi/2} \cos(\pi/2) = 0

g is a differentiable function; therefore, it is a continuous function, which tells us \lim_{x \to \pi/2} g(x) = g(\pi/2) = 0.

When we observe the limit  \displaystyle \lim_{x \to \pi/2} \frac{f(x)}{g(x)}, the numerator and denominator both approach zero. Thus we use L'Hospital's rule to evaluate the limit.

\displaystyle\lim_{x \to \pi/2} \frac{f(x)}{g(x)} = \lim_{x \to \pi/2} \frac{f'(x)}{g'(x)} = \frac{f'(\pi/2)}{g'(\pi/2)}

f'(\pi/2) = e^{\pi/2} \big( \cos(\pi/2) - \sin(\pi/2)\big) = -e^{\pi/2} \\ \\&#10;g'(\pi/2) = 2

thus

\displaystyle\lim_{x \to \pi/2} \frac{f(x)}{g(x)} = \frac{-e^{\pi/2}}{2}</span>

3 0
3 years ago
What is the product?<br><br> (6.45×106)⋅720,000
Nonamiya [84]
<span>(6.45×106)⋅720,000
=</span>(6.45×10^6) * (7.2×10^5)
=46.44 ×10^11
=4.644×10^12
5 0
3 years ago
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