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aksik [14]
3 years ago
6

In the final stage of the nuclear fuel cycle, the spent fuel must be transported, processed, and disposed of properly. True Fals

e
Chemistry
2 answers:
Aleksandr [31]3 years ago
8 0
True
After the process of Ore processing, Enrichment, Fuel production and being passed through the reactor core the last remaining step is spent fuel disposal. 
liubo4ka [24]3 years ago
4 0

Answer:

true

Explanation:

i took a quiz on it and got it right

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Select the word or phrase that best completes each of the following sentences.
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Answer:

1. Cells

2. Molecules

3. Organ

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At 40 Centigrade kW is?
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yee

Explanation:yee

3 0
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Wha twill form an acidic solution in water?
Mariulka [41]

Answer:

A strong acid

Any strong acid (such as HCl, HBr, or HNO_{3}) will completely dissociate forming a very weak conjugate base and H3O which will be acidic.

8 0
3 years ago
A lab experiment shows: merge a litmus paper in a
ddd [48]

Answer:

2.

Explanation:

When you put the paper in a solution, it will turn blue if it is basic, or red if it is acidic. If it does not change color, it is fairly neutral.

6 0
3 years ago
If the mass of the baking soda before the reaction was 10 grams and the mass of the vinegar was 15 grams and all of the baking s
Masteriza [31]

Answer:

8.946g NaHCO₃,

14.475g H₂O,

1.025g CH₃COO⁻Na⁺,

0.500g CO₂.

Explanation:

Baking soda (NaHCO₃) reacts with vinegar (CH₃COOH 5%) producing  CH₃COO⁻Na⁺, H₂O and CO₂, thus:

NaHCO₃ + CH₃COOH → CH₃COO⁻Na⁺ + H₂O + CO₂

10g of NaHCO₃ are:

10g × (1mol / 84g) = 0.119 moles NaHCO₃

Moles of CH₃COOH in 15g of vinegar are:

15g vinegar × 5% = 0.75g CH₃COOH × (1mol / 60g) = 0.0125moles CH₃ COOH

After reaction, moles of NaHCO₃ that remains are:

0.119mol - 0.0125mol = <em>0.1065 moles NaHCO₃</em>

In mass:

0.1065mol ₓ (84g / 1mol) = <em>8.946g NaHCO₃</em>

Acetic acid reacts completely producing  0.0125moles of CH₃COO⁻Na⁺, water and CO₂. In mass:

CH₃COO⁻Na⁺ = 0.0125mol ₓ (82.03g / 1mol) = <em>1.025g CH₃COO⁻Na⁺</em>

H₂O = 0.0125mol ₓ (18.01g / 1mol) = <em>0.225g H₂O</em>

CO₂ = 0.0125mol ₓ (40g / 1mol) = <em>0.500g CO₂</em>

Now, 95% of vinegar is water (Doesn't react), that is:

15g × 95% = 14.25g H₂O. Total mass of water is:

14.25g + 0.225g = <em>14.475g H₂O</em>

<em></em>

Total mass is:

8.946g + 14.475g H₂O + 1.025g + 0.500g ≈ 25g. The same than initial mass following law of conservation of matter.

6 0
3 years ago
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