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3 years ago

If two atoms of sodium combine with one molecule of chlorine which of the following could be a product

1 answer:

6 0

Sodium is a considered a metal and chlorine is a halogen and a nonmetal. When these elements come together they form, what we call an ionic compound. Specifically NaCl. Chlorine is a diatomic element. Which means chlorine is in a Cl2 form. Two mole of Na and 1 mole of Cl2 makes 2 moles of NaCl or sodium chloride or table salt.

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most planets have --- but none has a --- like earth does. A. a biosphere; hydrosphere., B. an atmosphere; cryosphere., C. an atm

liraira [26]

C. is the answer. i know because i had this question not that long ago.

5 0

3 years ago

Read 2 more answers

What is the [Na2SO4] (MM = 142.04 g/mol) in ppt if 100.00 mL of a

Ugo [173]

Answer:

1.345

Explanation:

I THINK SORRY

7 0

2 years ago

How many molecules of sodium chloride are in 2.5 moles??

sergiy2304 [10]

Answer:

1.5x1024

Explanation:

7 0

2 years ago

The vapor pressure of ethanol is 30°C at 98.5 mmHg and the heat of vaporization is 39.3 kJ/mol. Determine the normal boiling poi

Gelneren [198K]

Answer : The normal boiling point of ethanol will be, $348.67K$ or $75.67^oC$

Explanation :

The Clausius- Clapeyron equation is :

$\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})$

where,

$P_1$ = vapor pressure of ethanol at $30^oC$ = 98.5 mmHg

$P_2$ = vapor pressure of ethanol at normal boiling point = 1 atm = 760 mmHg

$T_1$ = temperature of ethanol = $30^oC=273+30=303K$

$T_2$ = normal boiling point of ethanol = ?

$\Delta H_{vap}$ = heat of vaporization = 39.3 kJ/mole = 39300 J/mole

R = universal constant = 8.314 J/K.mole

Now put all the given values in the above formula, we get:

$\ln (\frac{760mmHg}{98.5mmHg})=\frac{39300J/mole}{8.314J/K.mole}\times (\frac{1}{303K}-\frac{1}{T_2})$

$T_2=348.67K=348.67-273=75.67^oC$

Hence, the normal boiling point of ethanol will be, $348.67K$ or $75.67^oC$

3 0

3 years ago

Given the reaction: A + B <--> C + D

Lady_Fox [76]

Answer:

A.) 4.0

Explanation:

The general equilibrium expression looks like this:

$K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }$

In this expression,

-----> K = equilibrium constant

-----> uppercase letters = molarity

-----> lowercase letters = balanced equation coefficients

In this case, the molarity's do not need to be raised to any numbers because the coefficients in the balanced equation are all 1. You can find the constant by plugging the given molarities into the equation and simplifying.

$K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }$ <----- Equilibrium expression

$K = \frac{[2 M] [2 M]}{[1 M] [1 M] }$ <----- Insert molarities

$K = \frac{4}{1 }$ <----- Multiply

$K = 4$ <----- Divide

6 0

2 years ago