Answer:
Mass = 9.8 g
Explanation:
Given data:
Molarity of solution = 0.2 M
Volume of solution = 500 mL
Number of grams of phosphoric acid = ?
Solution:
First of all we will convert the volume milliliter to litter.
500 mL × 1 L/1000 mL
0.5 L
Molarity = moles of solute / volume in litter
0.2 M = number of moles / volume in litter
Number of moles = 0.2 mol/L × 0.5 L
Number of moles = 0.1 mol
Number of grams:
Number of moles = mass/molar mass
Mass = number of moles × molar mass
Mass = 0.1 mol × 98 g/mol
Mass = 9.8 g
Answer:
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Answer:
The correct answer is option C.
Explanation:
A. The -COOH group would experience hydrogen bonding with water.
The statement is true because , double bonded oxygen atom of carboxylic group interacts with hydrogen atom of water molecule and oxygen atom of water molecule is in same interaction with hydrogen atom of carboxylic acid.
B. The long alkane ''tail"
, is hydrophobic.
The statement is true because , region which do not interacts with water molecule is termed as hydrophobic region and region which do interacts with water molecule is termed as hydrophilic region. Generally ,alkanes are are hydrophobic in nature so is the alkane chain in stearic acid.
C. Stearic acid and water are probably miscible.
The statement is false because of higher hydrophobic region the interaction between the acid molecules and water molecules results in immiscibility.
D. Stearic acid would probably dissolve in non polar solvents such as hexane
.
The statement is true because of hydrophobic part in stearic acid is larger so that is why it get easily dissolve in non polar solvents.
E. Stearic acid contains hydrophobic regions
The statement is true because of higher hydrophobic region due to which they easily get dissolved in organic and non polar solvents.
The consumption of antacid affect urine pH by increasing the pH of urine. Sodium bicarbonate or antacid neutralizes the acidity in the stomach. It is expelled in the body through the urine by alkalizing it. Hope this answers the question.
Answer:
Heat required to melt 26.0 g of ice at its melting point is 8.66 kJ.
Explanation:
Number of moles of water in 26 g of water: 26×
moles
=1.44 moles
The enthalpy change for melting ice is called the entlaphy of fusion. Its value is 6.02 kj/mol.
we have relation as:
q = n × ΔH
where:
q = heat
n = moles
Δ
H = enthalpy
So calculating we get,
q= 1.44*6.02 kJ
q= 8.66 kJ
We require 8.66 kJ of energy to melt 26g of ice.