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jolli1 [7]
3 years ago
14

2. Water is an excellent solvent. With water being a polar

Chemistry
1 answer:
ladessa [460]3 years ago
7 0

Answer:

Water acts as a solvent of carbon dioxide excreted from tissues, in blood and helps in regulating pH (because it forms carbonic acid that lowers pH when it tends to get higher). Blood pH should be maintained at about 7.4. One major reason is that the structure of protein is dependent ton pH because pH determines its ionization hence also affecting the charges and interaction between side groups of amino acids. A change in pH may, therefore, denature proteins and negatively affect cellular functions.

Explanation:

To get more on how water acts as a universal solvent check out brainly.com/question/7007192

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A reaction takes place that results in an amount of 585 grams of product that is recovered. The theoretical amount calculates to
lisov135 [29]

Answer:

90%

Explanation:

Data obtained from the question include:

Actual yield = 585g

Theoretical yield = 650g

%yield =?

%yield = Actual yield /Theoretical yield x100

% yield = 585/650 x 100

% yield = 90%

7 0
4 years ago
Please help mee!! (brainliest) (elements)
Charra [1.4K]
MgCl2

————not sure with the answer
4 0
3 years ago
WHICH RIBBON WOULD BE CONSIDERED THE SENIOR RIBBON AND WOULD BE PLACED TO THE LEFT NEAR YOUR HEART?
Pie

Answer:

?

Explanation:

3 0
3 years ago
A trial of this decomposition experiment, using different quantities of reactants than those listed in the question above produc
Paul [167]

Answer : The volume of O_2(g) produced at standard conditions of temperature and pressure is 0.2422 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of O_2 gas = (740-22.4) torr = 717.6 torr

P_2 = final pressure of O_2 gas at STP= 760 torr

V_1 = initial volume of O_2 gas = 280 mL

V_2 = final volume of O_2 gas at STP = ?

T_1 = initial temperature of O_2 gas = 25^oC=273+25=298K

T_2 = final temperature of O_2 gas = 0^oC=273+0=273K

Now put all the given values in the above equation, we get:

\frac{717.6torr\times 280mL}{298K}=\frac{760torr\times V_2}{273K}

V_2=242.2mL=0.2422L

Therefore, the volume of O_2(g) produced at standard conditions of temperature and pressure is 0.2422 L

5 0
4 years ago
Please help How many moles of Pb(NO3)2 are required if 12 moles of Al(NO3)3 are produced
krok68 [10]
Answer is: 18 moles of lead(II)-nitrate.

Balanced chemical reaction: 
3Pb(NO₃)₂ + 2AlCl₃ → 2Al(NO₃)₃ + 3PbCl₂.
n(Al(NO₃)₃) = 12 mol.
From chemical reaction: nAl(NO₃)₃) : n(Pb(NO₃)₂) = 2 : 3.
n(Pb(NO₃)₂) = 3 · 12 mol ÷ 2.
n(Pb(NO₃)₂) = 18 mol; amount of substance.
Al(NO₃)₃ is aluminium nitrate.
AlCl₃ is aluminium chloride.

3 0
3 years ago
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