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3 years ago

If f(x) and f^-1(X) are inverse functions of each other and f(x)=2x+5, what I f^-1(8)

Mathematics

1 answer:

podryga [215]3 years ago

3 0

Answer: 3/5

Step-by-step explanation:

First, you need to find the inverse of f(x)=2x+5 .

$f-1(x)= \frac{x}{2} -\frac{5}{2}$

Then, you'd plug in 8 into that equation, which I got $\frac{3}{5\\}$

Hope this helps :)

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diamong [38]

y=6x-3

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3 years ago

Greta wants to make 5 pounds of a nut mix using peanuts and cashews. Her budget requires the mixture to cost her $6 per pound. P

Vinil7 [7]

Answer:

3 pounds of peanuts and 2 pounds of cashews

Step-by-step explanation:

Let x be the pounds of peanuts and y be the pounds of cashews

Greta wants to make 5 pounds of a nut mix using peanuts and cashews.

So, $x+y=5$ ----- A

Cost of 1 pound of peanuts = $4

Cost of x pounds of peanuts = 4x

Cost of 1 pound of cashews = $9

Cost of y pounds of cashews = 9y

Her budget requires the mixture to cost her $6 per pound

So, cost of mixture of x pounds of peanuts and y pounds of cashews is 6(x+y)

So, $4x+9y=6(x+y)$ --- B

Plot A and B

$x+y=5$ ---Blue

$4x+9x=6(x+y)$ ---Green

Refer the attached figure

Intersection point = (x,y)=(3,2)

Hence she should use 3 pounds of peanuts and 2 pounds of cashews

6 0

3 years ago

The table shows the results of a poll of 200 randomly selected juniors and seniors who were asked if they attended prom. Find th

Zielflug [23.3K]

Answer:

(a) $\frac{7}{25}$

(b) $\frac{19}{116}$

Step-by-step explanation:

Number of juniors who attended prom,n(J)=28

Number of seniors who attended prom,n(S)=97

Total of those who attended prom=125

Number of juniors who did not attend prom,n(J')=56

Number of seniors who did not attend prom,n(S')=19

Total of those who attended prom=75
Total Number of students=200

(a) P (a junior who did not attend prom)

$P(J')=\frac{56}{200}= \frac{7}{25}$

(b)

$P(Senior)=\frac{116}{200}$

$P ($did not attend prom$ | senior)=\frac{\text{P(seniors who did not attend prom)}}{P(Senior)} \\=\frac{19/200}{116/200} \\=\frac{19}{116}$

(c)P (junior | attended prom)

$P(Senior)=\frac{84}{200}$

$P (Junior|$ attended prom$)=\frac{\text{P(juniors who attended prom)}}{P(\text{those who attended prom)}} \\=\frac{28/200}{125/200} \\=\frac{28}{125}$

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malfutka [58]

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