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2 years ago

How many solutions exist for the system of equations graphed below? Help please !

Mathematics

2 answers:

Anika [276]2 years ago

7 0

Answer:

none

Step-by-step explanation:

kiruha [24]2 years ago

5 0

Answer:

none (0) ...

think of two lines (or chop sticks places on a table) ...

there are three (3) possible orientations that they can be in.

1) they cross each other at one point

2) they are on top of each other (they touch everywhere)

3) they are side by side (parallel)

in situation one we say we have a solution

in situation two we say there is an infinite solutions (the same line)

in situation three (your problem) we say there is no solution (parallel lines)

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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WORD PROBLEM! Sally has 15 apples. She gives some of her apples to three friends. They each get the same amount. Sally now has 9

Roman55 [17]

Answer:

Each friend got 2 apples

Step-by-step explanation:

[original amount of apples]-[Apples Sally has after distribution] = [friends] x [number of apples]

Filling in the brackets, you get this equation.

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gtnhenbr [62]

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3 years ago

Find the value of z A.110 B.141 C.80 D.100

gladu [14]

Answer:

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2 years ago

Find the equation of the line that passes through (1,3) and is perpendicular to y = 1 − 2 x

egoroff_w [7]

Answer:

$y=\displaystyle\frac{1}{2} x+\displaystyle \frac{5}{2}$

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept.

Perpendicular lines always have slopes that are negative reciprocals (ex. 1/2 and -2, 3/4 and -4/3)

Determine the slope (m):

$y = 1 -2x$

Rearrange into slope-intercept form:

$y = -2x+1$

Now, we can identify clearly that the slope is -2. Because perpendicular lines always have slopes that are negative reciprocals, a perpendicular line would have a slope of $\displaystyle\frac{1}{2}$ . Plug this into $y=mx+b$ :

$y=\displaystyle\frac{1}{2} x+b$

Determine the y-intercept (b):

$y=\displaystyle\frac{1}{2} x+b$

Plug in the given point (1,3) and solve for b:

$3=\displaystyle\frac{1}{2} *1+b\\\\b=\displaystyle \frac{5}{2}$

Therefore, the y-intercept is $\displaystyle \frac{5}{2}$ . Plug this back into $y=\displaystyle\frac{1}{2} x+b$ :

$y=\displaystyle\frac{1}{2} x+\displaystyle \frac{5}{2}$

I hope this helps!

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2 years ago