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3 years ago

How many solutions exist for the system of equations graphed below? Help please !

Mathematics

2 answers:

Anika [276]3 years ago

7 0

Answer:

none

Step-by-step explanation:

kiruha [24]3 years ago

5 0

Answer:

none (0) ...

think of two lines (or chop sticks places on a table) ...

there are three (3) possible orientations that they can be in.

1) they cross each other at one point

2) they are on top of each other (they touch everywhere)

3) they are side by side (parallel)

in situation one we say we have a solution

in situation two we say there is an infinite solutions (the same line)

in situation three (your problem) we say there is no solution (parallel lines)

Step-by-step explanation:

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If i am correctthe answer is
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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

At the beginning of the first day, Ann has 25 dollars. By the end of the first day, Ann has 2/3 of the money that she had at the

ira [324]

Answer:

Ann have at the end of the second day $\$9\frac{11}{21}.$

Step-by-step explanation:

Given:

At the beginning of the first day, Ann has 25 dollars.

By the end of the first day, Ann has 2/3 of the money that she had at the beginning of the first day.

By the end of the second day, Ann has 4/7 of the money that she had at the end of the first day.

Now, to find the money Ann have at the end of the second day.

Ann has at the beginning of the first day = $25.

At the end of the first day Ann had:

$\frac{2}{3} \ of\ 25$

$=\frac{2}{3} \times 25$

$=\$\frac{50}{3} .$

So, at the end of the first day Ann had $=\$\frac{50}{3} .$

Now, to get the money Ann have at the end of the second day:

$\frac{4}{7} \ of\ \frac{50}{3}$

$=\frac{4}{7} \times \frac{50}{3}$

$=\frac{200}{21}$

$=\$9\frac{11}{21} .$

Therefore, Ann have at the end of the second day $\$9\frac{11}{21}.$

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3 years ago

Help help please is my final please

tamaranim1 [39]

Answer:

d. 5

Step-by-step explanation:

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Answer:

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