Answer:
Get a line of which you want to know the slope. Make sure that the line is straight.
Pick any two coordinates that the line goes through. Coordinates are the x and y points written as ( x, y ).
Pick which point's coordinates are dominant in your equation. ...
Set up the equation using the y-coordinates on top and the x-coordinates on bottom.
The given equations are incomprehensible, I'm afraid...
You're given that osmium-183 has a half-life of 12 hours, so for some initial mass <em>M</em>₀, the mass after 12 hours is half that:
1/2 <em>M</em>₀ = <em>M</em>₀ exp(12<em>k</em>)
for some decay constant <em>k</em>. Solve for this <em>k</em> :
1/2 = exp(12<em>k</em>)
ln(1/2) = 12<em>k</em>
<em>k</em> = 1/12 ln(1/2) = - ln(2)/12
Now for some starting mass <em>M</em>₀, the mass <em>M</em> remaining after time <em>t</em> is given by
<em>M</em> = <em>M</em>₀ exp(<em>kt </em>)
So if <em>M</em>₀ = 590 g and <em>t</em> = 36 h, plugging these into the equation with the previously determined value of <em>k</em> gives
<em>M</em> = 590 exp(36<em>k</em>) = 73.75
so 73.75 ≈ 74 g of Os-183 are left.
Alternatively, notice that the given time period of 36 hours is simply 3 times the half-life of 12 hours, so 1/2³ = 1/8 of the starting amount of Os-183 is left:
590/8 = 73.75 ≈ 74
Answer:
1000 / 10 = 100 strikes per second. Now, multiply by 12 to find the number of strikes that occurred. 100 * 12 = 1200 strikes in 12 seconds. Part B: Divide the number of seconds to the number of lightning strikes to find the average rate. 10 / 1000 = 0.1 seconds per strike. Now, multiply by 7250 to find the number of seconds that passed.
Step-by-step explanation:
Answer:
225 students scored 65 or better and 75 students scored 88 or better.
Step-by-step explanation:
We are given that The five-number summary for the scores of 300 nursing students are given :
Minimum = 40

Median = 82

Maximum = 100
is the first quartile and is the median of the lower half of the data set. 25% of the numbers in the data set lie below
and about 75% lie above
.
is the third quartile and is the median of the upper half of the data set. 75% of the numbers in the data set lie below
and about 25% lie above 
i) .About how many students scored 65 or better?

Since we know that 75% lie above
.
So, Number of students scored 65 or better = 
ii)About how many students scored 88 or better?

Since we know that 25% lie above
So, Number of students scored 88 or better = 
Hence 225 students scored 65 or better and 75 students scored 88 or better.