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3 years ago

Given b(x)=|x+4|, what is b(-10)? A.-10 b. -6 c. 6 d. 14

2 answers:

5 0

The equation that they have given is an absolute function meaning any outcome in this function will be POSITIVE no matter what.
For example
B(-6) = l-6 + 4l
B(-6) = l-2l or B(-6) = 2

YOUR ANSWER

B(-10) = l -10 + 4l
B(-10) = l-6l or B (-10) = 6

so therefore your answer is C. 6

maks197457 [2]3 years ago

4 0

$f(x)=\begin{cases} x \geq 0 \implies |x| = x \\ x \ \textless \ 0 \implies |x|=-x \end{cases} \\ \\ b(x)=|x+4| \\ \\ b(-10)=|-10+4| = |-6| = -(-6)=6$

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2 years ago

A student who correctly answered 60 questions a test received a score of 75%. How many questions were on the test

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3 years ago

The half-life of the isotope Osmium-183 is 12 hours. Choose the equation below that gives the remaining mass of Osmium-183 in gr

raketka [301]

The given equations are incomprehensible, I'm afraid...

You're given that osmium-183 has a half-life of 12 hours, so for some initial mass M₀, the mass after 12 hours is half that:

1/2 M₀ = M₀ exp(12k)

for some decay constant k. Solve for this k :

1/2 = exp(12k)

ln(1/2) = 12k

k = 1/12 ln(1/2) = - ln(2)/12

Now for some starting mass M₀, the mass M remaining after time t is given by

M = M₀ exp(kt )

So if M₀ = 590 g and t = 36 h, plugging these into the equation with the previously determined value of k gives

M = 590 exp(36k) = 73.75

so 73.75 ≈ 74 g of Os-183 are left.

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3 years ago

Lightning strikes Earth 1000 times in 10 seconds. How many seconds does it take for lightning to strike 7250 times? It takes sec

borishaifa [10]

Answer:

1000 / 10 = 100 strikes per second. Now, multiply by 12 to find the number of strikes that occurred. 100 * 12 = 1200 strikes in 12 seconds. Part B: Divide the number of seconds to the number of lightning strikes to find the average rate. 10 / 1000 = 0.1 seconds per strike. Now, multiply by 7250 to find the number of seconds that passed.

Step-by-step explanation:

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3 years ago

Suppose 300 nursing students took a certification test that is worth 100 points.

Alja [10]

Answer:

225 students scored 65 or better and 75 students scored 88 or better.

Step-by-step explanation:

We are given that The five-number summary for the scores of 300 nursing students are given :

Minimum = 40

$Q_1 = 65$

Median = 82

$Q_3 = 88$

Maximum = 100

$Q_1$ is the first quartile and is the median of the lower half of the data set. 25% of the numbers in the data set lie below $Q_1$ and about 75% lie above $Q_1$ .

$Q_3$ is the third quartile and is the median of the upper half of the data set. 75% of the numbers in the data set lie below $Q_3$ and about 25% lie above $Q_3$

i) .About how many students scored 65 or better?

$Q_1 = 65$

Since we know that 75% lie above $Q_1$ .

So, Number of students scored 65 or better = $75\% \times 300 = \frac{75}{100} \times 300 =225$

ii)About how many students scored 88 or better?

$Q_3 = 88$

Since we know that 25% lie above $Q_3$

So, Number of students scored 88 or better = $25\% \times 300 = \frac{25}{100} \times 300 =75$

Hence 225 students scored 65 or better and 75 students scored 88 or better.

7 0

3 years ago