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Sedaia [141]
3 years ago
9

What is the value of the 6 In the number 48.061

Mathematics
2 answers:
Gnesinka [82]3 years ago
7 0

Answer:

Hundredth place

irga5000 [103]3 years ago
3 0

Answer:

.06 or six hundredths

Step-by-step explanation:

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The graph of a linear function intersects with the x axis at a point with an abscissa of 4 and with the y axis at a point with a
goldenfox [79]
We know that

points are
x intercept
A (4,0)

y intercept
B (0,11)

step 1
find the equation of a line
m=(y2-y1)/(x2-x1)--------> m=(11-0)/(0-4)------> m=-11/4

with m and the point B (0,11)
y-y1=m*(x-x1)y-11=(-11/4)*(x-0)---------> y=-(11/4)x+11

the answer is 
the formula of the function is y=-(11/4)x+11

see the attached figure

7 0
3 years ago
Area of a triangle with points at (-9,5), (6,10), and (2,-10)
Ann [662]
First we are going to draw the triangle using the given coordinates. 
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Distance from point A to point B:
d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}
d_{AB}= \sqrt{(6+9)^2+(10-5)^2}
d_{AB}= \sqrt{(15)^2+(5)^2}
d_{AB}= \sqrt{225+25}
d_{AB}= \sqrt{250}
d_{AB}=15.81

Distance from point A to point C:
d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}
d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}
d_{AC}= \sqrt{11^2+(-15)^2}
d_{AC}= \sqrt{121+225}
d_{AC}= \sqrt{346}
d_{AC}= 18.60

Distance from point B from point C
d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}
d_{BC}= \sqrt{(-4)^2+(-20)^2}
d_{BC}= \sqrt{16+400}
d_{BC}= \sqrt{416}
d_{BC}=20.40

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
s= \frac{AB+AC+BC}{2}
s= \frac{15.81+18.60+20.40}{2}
s= \frac{54.81}{2}
s=27.41

Finally, to find the area of our triangle, we are going to use Heron's formula:
A= \sqrt{s(s-AB)(s-AC)(s-BC)}
A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}
A= \sqrt{27.41(11.6)(8.81)(7.01)}
A=140.13

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0
3 years ago
Refer to your math writing journal file named "Lines and Angles." What real-world examples did you describe for the three ways i
Sav [38]

Answer:

  1. Railway lines are example of parallel lines
  2. The floor and the walls of a room are example of perpendicular lines
  3. Two roads crossing at a signal can be termed as example of intersecting lines

Step-by-step explanation:

The lines can be related in following three ways

  1. Lines can be parallel
  2. Lines can be perpendicular
  3. Lines can be intersecting at an angle other than 90.

Now three real life examples of above three scenarios are described below:

  1. Railway lines are example of parallel lines
  2. The floor and the walls of a room are example of perpendicular lines
  3. Two roads crossing at a signal can be termed as example of intersecting lines
6 0
3 years ago
Reuben invested his savings in two investment funds. The amount he invested in Fund A was 3 times as much as the amount he inves
andreyandreev [35.5K]

Answer:

5/100×1710=20

1710÷20=85.5 dollers

8 0
3 years ago
Mattttttthhhhhhhhhhhhhh , i need help
ale4655 [162]

The slope-point formula:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have (0, 3) and (-10, 4)

Substitute:

m=\dfrac{4-3}{-10-0}=\dfrac{1}{-10}\\\\y-3=-\dfrac{1}{10}(x-0)\qquad|\text{add 3 to both sides}\\\\y=-\dfrac{1}{10}x+3\to\boxed{A.}

3 0
3 years ago
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