Aye daddy
Lucky thing i just came back xD
Its 78.66 to the nearest sig fig
U can google it 2
Since it takes 4ever to type it out i wrote it intead srry if its messy lol
Answer:
It will lose 2 electrons
Explanation:
Here we have a calcium atom, which has 20 electrons.
Those 20 electrons are in 4 shells. (2-8-8-2)
Saying there are 2 electrons in the valence shell (Shell N), to get to an octet with an ionic bond (with a group 16 element), those 2 electrons will have to go.
When Kb = 1.1 x 10^-6
∴ Ka = Kw / Kb
= 1.1 x 10^-14 / (1.1 x 10 ^-6)
= 1 x 10^-8
when the reaction equation when we assume the base is B
B + H2O ↔ BH+ + OH-
∴ Ka = [BH+][OH-]/[B]
1 x 10^-8 = X^2 / 0.49
X^2 = 4.9 x 10^-9
∴X = 7 x 10^-5
∴[OH-] = 7 x 10^-5
∴POH = -㏒[OH]
= -㏒7 x 10^-5
= 4.15
∴ PH = 14 - POH
14 - 4.15
= 9.85
Answer:
Explanation:
2Al(s) + 3 I₂(s) → 2 Al⁺³ + 6 I⁻
Aluminium is oxidised and iodine is reduced .
so cell potential = Ereduction - Eoxidation
Al⁺³ + 3e = Al - 1.66 V
I₂ + 2 e = 2 I⁻ 0.54 V
= .54 - ( - 1.66 )
= 1.66 + .54
= 2.2 V
