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fiasKO [112]
3 years ago
5

100 Points Will Make Brainliest. Help Me Please.

Chemistry
2 answers:
Gnoma [55]3 years ago
6 0

Answer:

rubber gloves and glasses

Explanation:

rubber gloves and glasses

Oksana_A [137]3 years ago
3 0

If the glasses and glove were wrong then I would chose the fire extinguisher and the power source should be the correct answer.

That's just what I would do though.

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Ocean water contains 3.5 nacl by mass. what mass of ocean water in grams contains 45.8 g of nacl
Romashka-Z-Leto [24]

Mass percentage of sodium chloride(NaCl) in ocean waters = 3.5 %

That means 3.5 g sodium chloride(NaCl) is present for every 100 g of ocean water.

The given mass of sodium chloride(NaCl) is 45.8 g

Calculating the mass of ocean waters that would contain 45.8 g sodium chloride(NaCl):

45.8 g NaCl *\frac{100g ocean water}{3.5g NaCl}

                     = 1309 g ocean water

Therefore, 45.8 g sodium chloride is present in 1309 g ocean water.

3 0
3 years ago
To what volume should 25ml of 15m nitric acid be diluted to prepare a 3m solution
Maurinko [17]

We can use the dilution formula to find the volume of the diluted solution to be prepared

c1v1 = c2v2

Where c1 is concentration and v1 is volume of the concentrated solution

And c2 is concentration and v2 is volume of the diluted solution to be prepared

Substituting the values in the equation

15 M x 25 mL = 3 M x v2

v2 = 125 mL

The 25 mL concentrated solution should be diluted with distilled water upto 125 mL to make a 3 M solution

6 0
3 years ago
You're at the zoo and have a big red 1.80 L helium balloon. The barometric pressure today is 785 mmHg. Then you hear the roar of
fomenos

Answer: The volume of the balloon up there is 6.192 L.

Explanation:

Given: V_{1} = 1.80 L,    P_{1} = 785 mm Hg (mm Hg = 0.00131579) = 1.032 atm

P_{2} = 0.300 atm,       V_{2} = ?

Formula used to calculate volume is as follows.

P_{1}V_{1} = P_{2}V_{2}

Substitute the value into above formula as follows.

P_{1}V_{1} = P_{2}V_{2}\\1.032 atm \times 1.80 L = 0.300 atm \times V_{2}\\V_{2} = 6.192 L

Thus, we can conclude that the volume of the balloon up there is 6.192 L.

8 0
3 years ago
Can someone please help me with this it's for a grade.
alukav5142 [94]

Answer:

The Answer is 'D'

Explanation:

The diagram on the down side shows the behavior of the particles of a liquid so I suppose it is the ocean. While the top diagram shows the behavior of the particles of a gas so I am sure it's the air. Therefore I chose the last diagram because it describes exactly how you wanted in the question, which is the Ocean's water evaporating to become gas or the 'air' as we say

<em>Thank</em><em> </em><em>you</em><em> </em><em>and</em><em> </em><em>I</em><em> </em><em>hope</em><em> </em><em>you</em><em> </em><em>like this</em><em> </em><em>answer</em><em>! </em>

7 0
3 years ago
A certain electrolyte solution contains 1 gram of salt for every 8 grams of sugar and every 200 grams of water. If the sugar to
12345 [234]

Answer:

The resulting solution contains approximately 666 g of water.

Explanation:

In the initial solution we have:

1g salt : 8g sugar : 200g water

This means that the ratios are:

\frac{salt}{sugar}  = \frac{1}{8} \\\\\frac{sugar}{water} = \frac{8}{200} =\frac{1}{25}

In the final solution we have:

5g salt: xg sugar: yg water

The new ratios are:

\frac{salt}{sugar} = \frac{3}{8} \\\\\frac{sugar}{water} = \frac{1}{50}

Now we can calculate the amount of sugar in the final solution:

\frac{salt}{sugar}  = \frac{5}{x} =\frac{3}{8} \\\\X = 13.333 g

Finally, we calculate the amount of water:

\frac{sugar}{water} = \frac{13.333}{y} = \frac{1}{50} \\y = 666.667 g

4 0
3 years ago
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