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3 years ago

100 Points Will Make Brainliest. Help Me Please.

Chemistry

2 answers:

Gnoma [55]3 years ago

6 0

Answer:

rubber gloves and glasses

Explanation:

rubber gloves and glasses

Oksana_A [137]3 years ago

3 0

If the glasses and glove were wrong then I would chose the fire extinguisher and the power source should be the correct answer.

That's just what I would do though.

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Because the the individual components of any mixture are not _____ to each other, the composition of those components can vary.

Alla [95]

Answer:

Because the individual components of any mixture are not bonded to each other, the composition of those components can vary. Also, some of the physical properties of the individual components are still noticeable.

Explanation:

A mixture is a combination of two or more pure substances that are present in any proportion and each pure substance keeps its own physical and chemical properties.

As oppossite to mixtures, the compounds are pure substances formed by two or more different elements which are chemically bonded to each other. So, while in the compounds the components (elements) are bonded in a fixed proportion, and their composition cannot vary, in the mixtures each component may be present in any proportion, which means that the composition can vary.

Take, for example, the simple case of talc and iron particles.This is a mixture. Talc is not bonded to the iron particles, and so their proportion, the compositoin, can vary in any form. Aslo, both talc and iron particles keep their own physical properties: you can perfectly separate the mixture by using a magnet to attract the iron particles, because they have not lost their magnetic property (a physical one).

4 0

3 years ago

State the periodic table

kogti [31]

Answer:

Heres a picture of the periodic table.

Explanation:

Source(s):Science News for Students

5 0

3 years ago

How should the enthalpy of an intermediate step be manipulated when used to produce an overall chemical equation?

White raven [17]

The enthalpy of an intermediate step should be manipulated when used to produce an overall equation by using the Hess's law. You could multiply the enthalpy by -1 if this equation is reversed in theory.

8 0

3 years ago

Which of the following is NOT a derived unit? a) <img src="https://tex.z-dn.net/?f=cm%5E%7B3%7D" id="TexFormula1" title="

seraphim [82]

Answer:

c) kg

Explanation:

Kilograms stands alone. It has to be hooked up to another unit for it to be a derived unit.

I am joyous to assist you anytime.

4 0

3 years ago

Read 2 more answers

What is the predicted change in the boiling point of water when 1.50 g of

dezoksy [38]

Answer:

0.00735°C

Explanation:

By seeing the question, we can see the elevation in boiling point with addition of BaCl₂ in water

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$\textsf {While} \: \sf {\Delta T_b} \: \textsf{expression is used} \\ \textsf {for elevation of boiling point}$

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The elevation in boiling point is a phenomenon in which there is increase in boiling point in solution, when the particular type of solute is added to pure solvent.

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$\sf \large \underline{The \: formula \: to \: be \: used \: in \: this \: question \: is} \\ \boxed{T_b = i \times K_b \times m}$

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Where 'i' is van't hoff factor which represents the ratio of observed osmotic pressure and the value to be expected.

and 'i' is 3 (as given in the question)

⠀

'Kb' is molal boiling point constant. And it's value is 0.51°C/mol(given in question)

⠀

'm' represent the molality of solution. Molatity is no. of moles of solution present in 1kg of solution.

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To find molality, we have to divide no. of moles of solute by weight of solution

⠀

While first we need to no. of moles

$\sf \implies no. \: of \: moles = \frac{weight \: of \: solute}{molar \: mass \: of \: solute} \\ \\ \implies \sf no. \: of \: moles = \frac{1.5}{208.23} \\ \\ \sf \implies no. \: of \: moles = 0.0072$

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Now, we will find molality

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$\sf \hookrightarrow molality = \frac{no.\: of \: moles}{weight \: of \: solution} \\ \\ \sf \hookrightarrow molality = \frac{0.072}{1.5} \\ \\ \sf \hookrightarrow molality = 0.048 \: mol {kg}^{ - 1}$

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$\textsf{ \large{ \underline{Now substituting the required values}}}$

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$\sf \longmapsto \Delta T_b = 3 \times 0.51 \times 0.0048 \\ \\ \\ \boxed{ \tt{ \longmapsto \Delta T_b =0.00735{ \degree}C}}$

⠀

Henceforth, the change in boiling point is 0.00735°C.

7 0

1 year ago