Ionization energy, also called ionization potential, in chemistry, the amount of energy required to remove an electron from an isolated atom or molecule.
Answer:
Ka= 2.3 x 10^-11
Explanation:
so Ka x Kb = Kw where Kw=10^-14 at 25 degrees Celsius
plugging in Kb and Kw, we have
Ka x 4.4 x 10^-4 = 10^-14
solving for Ka,
Ka= (10^-14)/(4.4 x 10^-4)
Ka= 2.3 x 10^-11
Answer:
68000J/kg
Explanation:
Given parameters:
Mass of the substance = 0.5kg
Quantity of heat transferred to the body = 34000J
Unknown:
Specific latent heat of fusion = ?
Solution:
The specific latent heat is usually involve in phase changes;
H = mL
H is the quantity of heat supplied
m is the mass
L is the specific latent heat
Insert the parameters and solve;
34000 = 0.5 x L
L =
= 68000J/kg
Answer:
6
Explanation:
bromine has 1, hydrogen has 4 and nitrogen has 1 therefore equaling 6