All categories

3 years ago

Explain the difference between natural and artificial satellites of earth annd moon

2 answers:

6 0

An artificial satellite is one that was manufactured by people ... most likely on Earth ... and then launched and placed into orbit around Earth, the sun, the moon, a planet, an asteroid etc.

Troyanec [42]3 years ago

6 0

Answer:

The difference between natural and artificial satellites are discussed below.

Explanation:

Natural satellite

A Natural Satellite is a heavenly body that orbits around another body.
Almost 173 known natural satellites are orbiting around the planets in the Solar system.
Earth also has its natural satellite that is known as the Moon.

Artificial satellite

An artificial satellite is the man-made celestial object that orbits around another object.
They remain in the orbit by the Gravitational force or pull of another body

You might be interested in

An object attached to one end of a spring makes 20 complete vibrations in 10s. Its frequency is:

Alexxandr [17]

Answer:

0.50 s

Explanation:

4 0

3 years ago

if you apply a net force of 5 N on a cart with a mass of 5 kg, show that the acceleration is one meter per second squared

lina2011 [118]

$*\\
From\ Newton's\ third\ Law:\\\\
acceleration=\frac{Net\ force}{mass}\\\\
Net\ force=5N\\
mass=5kg\\\\
acceleration=\frac{5N}{5kg}=1\frac{m}{s^2}$

3 0

3 years ago

A car has an initial velocity of 50 m/s and a constant

Rasek [7]

Vf=vi+at
Vf= (50m/s)+ (5m/s2)(3s)
Vf=65m/s

3 0

3 years ago

Do you think copper would have oxidized of it was completly submerged in vinigar

cluponka [151]

yes if it was submerged long enough

5 0

4 years ago

El monoxido de carbono reacciona con el hidrogeno gaseoso para producir metanol (ch3oh) calcule el reactivo limite y el reactivo

Orlov [11]

Answer:

Se obtienen 2,27 gramos de metanol.

Explanation:

La reacción entre monóxido de carbono e hidrógeno para producir metanol es la siguiente:

CO + 2H₂ → CH₃OH

Para encontrar el reactivo limitante y el reactivo en exceso, debemos calcular el número de moles de CO y H₂:

$\eta_{CO} = \frac{m}{M}$

En donde:

m: es la masa

M: es el peso molecular

$\eta_{CO} = \frac{m}{M_{CO}} = \frac{2,0 g}{28,01 g/mol} = 0,071 moles$

$\eta_{H_{2}} = \frac{2,0 g}{2,02 g/mol} = 0,99 moles$

Dado que la relación estequiométrica entre CO y H₂ es 1:2, el número de moles de hidrógeno gaseoso que reaccionan con el monóxido de carbono es:

$\eta_{H_{2}} = \frac{2}{1}*0,071 = 0,142 moles$

Entonces, se necesitan 0,142 moles de H₂ para reaccionar con 0,071 moles de CO y debido a que se tienen más moles de H₂ (0,99 moles) entonces el reactivo limitante es CO y el reactivo en exceso es H₂.

Ahora podemos encontar la masa de metanol obtenida usando el reactivo limitante (CO) y sabiendo que la realcion estequiométrica entre CO y CH₃OH es 1:1.

$\eta_{CH_{3}OH} = \eta_{CO} = 0,071 moles$

$m = 0,071 moles*32,04 g/mol = 2,27 g$

Por lo tanto, se obtienen 2,27 gramos de metanol.

Espero que te sea de utilidad!

6 0

3 years ago