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seropon [69]
3 years ago
7

A real image can be obtained with:

Physics
2 answers:
ahrayia [7]3 years ago
7 0

Answer:

c on edge

Explanation:

In-s [12.5K]3 years ago
4 0

Answer:

convex lens and a concave mirror

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A skier halfway between the top and bottom of a hill. Which statement best describes the skier?
Dvinal [7]

Answer: The skier has potential and kinetic energy.

Explanation: This is what I found from a different user on this website

5 0
3 years ago
Fill out the blanks, this is for science!
dusya [7]
Faster and higher I believe.
8 0
3 years ago
Read 2 more answers
Describe what would happen if you rubbed a mineral with a Mohs hardness value of 7 against a mineral with a value of 5?
chubhunter [2.5K]
The mineral with Mohs hardness would be scratched because the mineral with Mohs 7 hardness is stronger than the Mohs 5 mineral. Eventually, that mineral would turn into dust if you kept rubbing it.
8 0
3 years ago
A circuit is made of a battery, a light bulb, and a 2 resistor. The battery has a voltage of 3 volts. When connected, the ammete
Monica [59]

Answer:

3ohms

Explanation:

From Ohm's Law

V = IR

V is that voltage = 3volts

I = current = 1amp

R = resistance in ohms

Putting those values into the above formula.

3volts = 1amp×R

Making R the subject

R = 3/1

R = 3ohms

The resistance of the light bulb is 3ohms.

6 0
3 years ago
An object weighs 60.0 kg on the surface of the earth. How much does it weigh 4R from the surface? (5R from the center)
Alecsey [184]
"60 kg" is not a weight.  It's a mass, and it's always the same
no matter where the object goes.

The weight of the object is   

                                 (mass) x (gravity in the place where the object is) .

On the surface of the Earth,

                   Weight = (60 kg) x (9.8 m/s²)

                                =      588 Newtons.

Now, the force of gravity varies as the inverse of the square of the distance from the center of the Earth.
On the surface, the distance from the center of the Earth is 1R.
So if you move out to  5R  from the center, the gravity out there is

                    (1R/5R)²  =  (1/5)²  =  1/25  =  0.04 of its value on the surface.

The object's weight would also be 0.04 of its weight on the surface.

                 (0.04) x (588 Newtons)  =  23.52 Newtons.

Again, the object's mass is still 60 kg out there.
___________________________________________

If you have a textbook, or handout material, or a lesson DVD,
or a teacher, or an on-line unit, that says the object "weighs"
60 kilograms, then you should be raising a holy stink. 
You are being planted with sloppy, inaccurate, misleading
information, and it's going to be YOUR problem to UN-learn it later.
They owe you better material.
6 0
3 years ago
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