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seropon [69]
3 years ago
7

A real image can be obtained with:

Physics
2 answers:
ahrayia [7]3 years ago
7 0

Answer:

c on edge

Explanation:

In-s [12.5K]3 years ago
4 0

Answer:

convex lens and a concave mirror

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g stAn experienced spear fisherman sees a small fish swimming in a tidal pool. If the fisherman sees the fish at approximately a
Luba_88 [7]

Answer:

  θ = 28.9

Explanation:

For this exercise let's use the law of refraction

          n₁ sin θ₁ = n₂ sin θ₂

where we use index 1 for air and index 2 for water where the fish is

        sin θ₂ = n₁ / n₂ sin θ₁

in this case the air repair index is 1 and the water 1.33

we substitute

        sin θ₂ = 1 / 1.33 sin t 40

        sin θ = 0.4833

         

        θ = sin⁻¹ 0.4833

        θ = 28.9

5 0
3 years ago
Convert the number from scientific into standard notation: 5.9 x 10-2
guapka [62]
Move the decimal point to:
Left : (if the exponent of ten is a negative number -) ... OUR CASE HERE (-2)
or to
Right : (if the exponent is positive +).

You should move the point as many times as the exponent indicates.
Do not write the power of ten anymore.

So, standard form is:
Two points to the left {Exponent of Ten is Negative (-2)}
0.059 ... (without the 10)
6 0
2 years ago
Suppose the electric field in some region is found to be E = kr3 ˆr, in spherical coordinates (k is some constant). (a) Find the
Assoli18 [71]

Answer:

Part a)

\rho = 3\epsilon_0 k r^2

Part b)

Q = 4\pi \epsilon_0kR^5

Explanation:

Part a)

As we know that electric field intensity due to some given charge distribution is given as

E = kr^3 \hat r

now electric flux through a spherical surface of radius r is given as

\phi = E. A

\phi = kr^3(4\pi r^2)

now by Guass law we know that

E.A = \frac{q}{\epsilon_0}

q = 4\pi \epsilon_0kr^5

now volume charge density is given as

\rho = \frac{q}{\frac{4}{3}\pi r^3}

\rho = 3\epsilon_0 k r^2

Part b)

Total charge inside the radius R is given as

Q = 4\pi \epsilon_0kR^5

7 0
3 years ago
A vessel contains 1 mol of O2 and 2mol of He.what is the value of'Cp/Cv ' of the mixture?
BlackZzzverrR [31]
Oxygen is diatomic, so its degree of freedom, (f1)= 5,
also its number of moles, n1= 1


Helium is monoatomic, so its degree of freedom (f2)= 3 
and its number of moles given is, n2=2

Now using formula of effective degree of freedom of mixture, (f), we have: 

f= (f1n1+f2n2)/(n1+n2)
  =  (5*1 + 3*2)/ (1+3)
   =11/3
Also, from first law of thermodynamics;
U= n Cv. T = nRT(f2)
 or, Cv = R. (f/2) (n & T cancel)

We know f=11/6, 
substituting the value in above relation, we have:

Cv= R. 11/3*2
    = R. 11/6

Also, Cp-Cv = R
 or, Cp- R.(11/6)= R
or, Cp= R(11/6 )+1
          = 17/6 R

Therefore, Cp/Cv = 17/11
    




6 0
3 years ago
How can an electric current produce a magnetic field
anygoal [31]

Answer:

When the compass is placed below the wire, and the electric current switched on, the needle deflects in the opposite direction. If an electric current is passed through a long coil of wire (a solenoid ) a magnetic field is produced which is the same shape as that of a bar magnet.

Explanation:

8 0
3 years ago
Read 2 more answers
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