Answer:
a) θ = 65º , b) the light is refracted
Explanation:
When a ray of light passes from a material with a higher index to one with a lower index, the ray separates from the normal one, so there is an angle for which the ray is refracted at 90º, the refractive equation is
n₁ sin θ₁ = n₂
where θ₁ is the incident angle, n₂ and n₁ are the indexes of incident and refracted parts
let's calculate
sin θ = n₂ / n₁
sint θ = 1.3333 / 1.470
sin θ = 0.907
θ = sin⁻¹ 0.907
θ = 65º
For the incident angle of 50.2º it is less than the critical angle, so the light is refracted according to the refraction equation
-45N because you add the side together and make it equal 0
Answer:
Net force, F = 44.66 N
Explanation:
It is given by,
Initial velocity of the person, u = 0
Final velocity of the person, v = 0.68 m/s
Distance, s = 0.428 m
Combined mass of the person and the kayak, m = 82.7 kg
We need to find the net force acting on the kayak i.e.
F = ma...........(1)
Firstly, we will calculate the value of "a" from third equation of motion as :
Put the value of a in equation (1) as :
F = 44.66 N
So, the net force acting on the kayak is 44.66 N. Hence, this is the required solution.
Answer:
The distance covered by the body is, S = 800 m
Explanation:
Given data,
The initial velocity of the body, u = 30 m/s
The acceleration of the body, a = 10 m/s²
Let the time period of travel be, t = 10 s
Using the II equations of motion,
S = ut + ½ at²
Substituting the given values,
S = 30 x 10 + ½ x 10 x 10²
S = 800 m
Hence, the distance covered by the body is, S = 800 m
Answer:
The acceleration will also double
Explanation:
F = m*a
a = F/m
plugging in sample numbers to prove
a= 100/4 = 25
a = 200/4 = 50
