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Leona [35]
3 years ago
8

What is the change in internal energy if 70 J of heat is added to a system and

Physics
1 answer:
ValentinkaMS [17]3 years ago
4 0

Answer:

A. 40 J

Explanation:

Given;

heat added to the system, Q = 70 J

work done by the system, W = 30 J

The change in the internal energy of the system is calculated using the first law of thermodynamic as shown below;

ΔU = Q - W

ΔU = 70 J - 30 J

ΔU = 40 J

Therefore, the  change in the internal energy of the system is 40J

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(a) How much work is required to lift a 35-kg object from the ground 3.0 m into the air? (b) How much gravitational potential en
V125BC [204]

Answer:

(a) work required to lift the object is 1029 J

(b) the gravitational potential energy gained by this object is 1029 J

Explanation:

Given;

mass of the object, m = 35 kg

height through which the object was lifted, h = 3 m

(a) work required to lift the object

W = F x d

W = (mg) x h

W = 35 x 9.8 x 3

W = 1029 J

(b) the gravitational potential energy gained by this object is calculated as;

ΔP.E = Pf - Pi

where;

Pi is the initial gravitational potential energy, at initial height (hi = 0)

ΔP.E = (35 x 9.8 x 3) - (35 x 9.8 x 0)

ΔP.E = 1029 J

7 0
2 years ago
What patterns are caused by the Earth, Sun, and Moon systems?
MatroZZZ [7]

Answer: Solor cycles and tings

5 0
3 years ago
Read 2 more answers
A 0.0100-kilogram grape hangs from a vine 1.50 meters from the ground. What is the potential energy of the grape?
ludmilkaskok [199]
The potential energy is defined as Ep=m*g*h where m is the mass of the body, g=9.81 m/s² and h is the height of the body. In our case m=0.01 kg and h=1.5 m. So when we input the values into the equation:

Ep=0.01*9.81*1.5= 0.14715 J. 

So the potential energy of a grape is Ep=0.14715 J. 
8 0
3 years ago
Read 2 more answers
1. If the angle of the ramp were increased from 30˙ to 45˙, how would this change the weight of the box? Explain.
yawa3891 [41]

When the angle of the ramp increases, the weight of the box acting perpendicular to the ramp decreases.

<h3>Normal reaction of the box</h3>

The normal reaction of the box is due to weight of the box acting perpendicular to the ramp.

Fn = Wcosθ

<h3>when the angle of the ramp = 30⁰</h3>

Fn = Wcos(30)

Fn = 0.866W

<h3>when the angle of the ramp = 45⁰</h3>

Fn = W x cos(45)

Fn = 0.7071W

Thus, when the angle of the ramp increases, the weight of the box acting perpendicular to the ramp decreases.

Learn more about normal reaction here: brainly.com/question/18292235

#SPJ1

4 0
2 years ago
A lumberjack (mass = 103 kg) is standing at rest on one end of a floating log (mass = 255 kg) that is also at rest. The lumberja
mina [271]

Answer:

(a) -1.18 m/s

(b) 0.84 m/s

Explanation:

(a)

The total linear momentum before the lumberjack begins to move is zero because all parts of the system are at res

From the law of conservation of momentum

m1v1+m2v2=0 hence m1v1=-m2v2 where m1 is mass of lumberjack, v1 is velocity of lumberjeck, m2 is mass of floating log, v2 is velocity of the floating log.

Substituting M1 for 103 Kg, V1 for 2.93 m/s, M2 for 255 Kg into the above equation we obtain

103Kg*2.93 m/s=-255Kg*V2

V2=-(103 kg*2.93 m/s)/255=-1.183490196  m/s

Hence V2=-1.18 m/s

(b)

For the second log

V(M1+M2)=m1v1 where V is the common velocity

V(103 Kg+255 Kg)=103 Kg*2.93 m/s

V=(103 Kg*2.93 m/s)/(103 Kg+255 Kg)=0.842988827  m/s

V=0.84 m/s

6 0
2 years ago
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