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2 years ago

How is an interference pattern formed by a diffraction grating different from the pattern formed by a double slit

Physics

1 answer:

belka [17]2 years ago

8 0

Answer:

Evaluate the following numerical expressions.

6 + 3 • 4 =

(6 + 3) ÷ (4 – 5) =

Explanation:

Evaluate the following numerical expressions.

6 + 3 • 4 =

(6 + 3) ÷ (4 – 5) =

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Two drag cars race. They line up at the starting line at rest. The winning car accelerates at a constant rate a and reaches the

Mila [183]

Answer: $d=\frac{v^2}{8a}$

Explanation:

Given

winning car accelerates with a and its final velocity is v

considering they both start from rest

time taken by winning car is

v=u+at

where u=initial velocity

a=acceleration

t=time

$v=at$

$t=\frac{v}{a}$

Now loosing car is accelerating with $\frac{a}{4}$

Distance traveled by loosing car in time t

$s_1=ut+\frac{at^2}{2\cdot 4}$

$s_1=0+\frac{a}{8}\times (\frac{v}{a})^2$

$s_1=\frac{v^2}{8a}$

Thus distance d traveled by loosing car is given by $d=\frac{v^2}{8a}$

5 0

4 years ago

A 3 kg mass object is pushed 0.6 m into a spring with spring constant 210 N/m on a frictionless horizontal surface. Upon release

Aleksandr-060686 [28]

Answer with Explanation:

We are given that

Mass of spring,m=3 kg

Distance moved by object,d=0.6 m

Spring constant,k=210N/m

Height,h=1.5 m

a.Work done to compress the spring initially= $\frac{1}{2}kx^2=\frac{1}{2}(210)(0.6)^2=37.8J$

By conservation law of energy

Initial energy of spring=Kinetic energy of object

$37.8=\frac{1}{2}(3)v^2$

$v^2=\frac{37.8\times 2}{3}$

$v=\sqrt{\frac{37.8\times 2}{3}}$

v=5.02 m/s

c.Work done by friction on the incline, $w_{friction}=P.E-spring \;energy$

$W_{friction}=3\times 9.8\times 1.5-37.8=6.3 J$

3 0

3 years ago

Need help with these questions

Mice21 [21]

What grade is this?

I know this is not an answer, but I need to know to help you.

5 0

3 years ago

For an object being launched at ground level at a tilted non-zero initial velocity, is the velocity zero anywhere? are the horiz

borishaifa [10]

The correct answer No the velocity is not zero anywhere For an object being launched at ground level at a tilted non-zero initial velocity, and horizontal or vertical components of the velocity is zero at maximum height .

Because velocity is a vector (it has magnitude and direction), the overall velocity of an object can be calculated by adding the x and y components: v2 = vx2 + vy2. Meters are used to express horizontal and vertical distances (m). The horizontal velocity component (vx) describes the effect of velocity on horizontal displacement of the projectile.

The vertical velocity component (vy) describes the effect of velocity on vertical displacement of the projectile. The vertical component of a projectile's velocity is momentarily zero (vy = 0 m/s) when it reaches maximum height. The horizontal component of its velocity, however, is not zero.

Learn more about components of velocity here :-

brainly.com/question/12498991

#SPJ4

3 0

1 year ago

What is the answer to this question or problem

PilotLPTM [1.2K]

Number 16 is organ system

3 0

3 years ago