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Leni [432]
3 years ago
8

A line contains the points S (4, -10) and B (10, -16). Find the slope of SB ̅̅̅̅. Must show your work to receive full credit

Mathematics
1 answer:
Alborosie3 years ago
7 0

Answer:

The slope for this is -1.

Step-by-step explanation:

<em>First you want to put down the formula:</em>

<em><u>y^2 - y^1</u></em>

<em>x^2 - x^1</em>

<em>Fill it out and get your answer. </em>

<em>x^1=4</em>

<em>y^1=-10</em>

<em>x^2=10</em>

<em>y^2=-16</em>

<em>-belle :)</em>

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icang [17]

Answer:

You need to put the question, but I'll try to help as much as I can without the question. y=5/2x, if you put the amount of gummy candy in lbs in the x's place, and you multiply the amount by 5/2, you will get the price.

Step-by-step explanation:

7 0
3 years ago
How do you solve the inequality 12 &lt; x + 5 so that the variable "x" is on the left side?
Eduardwww [97]
The like terms are 12 and 5, so you have to subtract 5 from both sides.
12 < x + 5
-5. -5
7 < x
We can just switch it around so x is in the left side.
x > 7
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3 years ago
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Nine less than five times a number is equal to -30.
notka56 [123]

Answer: 5x-30-9

-159

Step-by-step explanation:

-159 is the answer

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3 years ago
According to Masterfoods, the company that manufactures M&amp;M’s, 12% of peanut M&amp;M’s are brown, 15% are yellow, 12% are re
Anna35 [415]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

P(brown) = 12% = 0.12

P(Yellow) = 15% = 0.15

P(Red) = 12% = 0.12

P(blue) = 23% = 0.23

P(orange) = 23% = 0.23

P(green) = 15% = 0.15

A.) Compute the probability that a randomly selected peanut M&M is not yellow.

P(not yellow) = P(Yellow)' = 1 - P(Yellow) = 1 - 0.15 = 0.85

B.) Compute the probability that a randomly selected peanut M&M is brown or red.

P(Brown) or P(Red) :

0.12 + 0.12 = 0.24

C.) Compute the probability that three randomly selected peanut M&M’s are all brown.

P(brown) * P(brown) * P(brown)

0.12 * 0.12 * 0.12 =0.001728

D.) If you randomly select three peanut M&M’s, compute that probability that none of them are blue.

P(3 blue)' = 1 - P(3 blue)

P(3 blue) = 0.23 * 0.23 * 0.23 = 0.012167

1 - P(3 blue) = 1 - 0.012167 = 0.987833

If you randomly select three peanut M&M’s, compute that probability that at least one of them is blue.

P(1 blue) + p(2 blue) + p(3 blue)

(0.23) + (0.23*0.23) + (0.23*0.23*0.23)

0.23 + 0.0529 + 0.012167

= 0.295067

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3 years ago
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Leona [35]
The x would equal 0 and the y would equal 3
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2 years ago
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