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atroni [7]
3 years ago
11

Does anyone know this?

Mathematics
1 answer:
vlabodo [156]3 years ago
5 0

i think is

14a5−10a3−16a+38416

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What is 0.66666666666 as a fraction
stellarik [79]

To turn 0.(6)=0.6666... into a fraction you should do such steps:

1 step. Set up an equation by representing the repeating decimal with a variable. Using your example, you will let x represent the repeating decimal 0.(6), so you have x=0.666... .

2 step. Identify how many digits are in the repeating pattern, or n digits. Multiply both sides of the equation from Step 1 by 10^n to create a new equation. Again, using your example, you see that the repeating pattern consists of just one digit: 6. Now multiply both sides of the equation by 10^1 = 10. Thus, you have 10x = 10 \cdot 0.666... or 10x = 6.666.....

3 step. Subtract the equation in Step 1 from the equation in Step 2. Notice that when we subtract these equations, our repeating pattern drops off. Therefore, 10x-x=6.666...-0.666...\\ 9x=6.

4 step. You now have an equation that you can solve for x and simplify as much as possible, using x as a fraction: 9x = 6. If you divide both sides by 9, you get x=\dfrac{6}{9}. When simplified, you get that x=\dfrac{2}{3}.

Answer: 0.(6)=0.666... =\dfrac{2}{3}.

8 0
3 years ago
Read 2 more answers
Help me idk how do do this ;-;
Kobotan [32]

Answer:

idk either

Step-by-step explanation:

8 0
3 years ago
(PLS HELP)<br> Choices:<br> A. 120cm<br> B. 117cm<br> C. 101cm<br> D. 350cm
weeeeeb [17]

Answer:

117

Step-by-step explanation:

13*9=117

6 0
2 years ago
Read 2 more answers
Which statement best describes a chord of a circle?
Ugo [173]
<span>A chord of a circle is a straight line segment whose endpoints both lie on the <span>circle
</span></span><span> The statement  that best describes a chord of a circle is 
</span>It is a segment that connects two distinct points on a circle
so the correct option is c
hope it helps
6 0
3 years ago
PLEASE HELP ME! TIMED!
erica [24]

Answer:

1.6-5 2.  42 3. 36/66

Step-by-step explanation:

6 0
2 years ago
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