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yaroslaw [1]
3 years ago
11

Solve the equation. \dfrac18 + c = \dfrac45 8 1 ​ +c= 5 4 ​ start fraction, 1, divided by, 8, end fraction, plus, c, equals, sta

rt fraction, 4, divided by, 5, end fraction c=c=c, equals
Mathematics
1 answer:
aivan3 [116]3 years ago
4 0

Answer:

c=\dfrac{27}{40}\\

Step-by-step explanation:

We are required to solve for c in the equation: \dfrac{1}{8}+c= \dfrac{4}{5}

Step 1: Collect like terms

\dfrac{1}{8}+c= \dfrac{4}{5}\\c= \dfrac{4}{5}-\dfrac{1}{8}

Step 2: Find the Lowest Common Multiple of the denominators

LCM of 8 and 5 is 40

Step 3: Multiply all through by 40

40c= \dfrac{4}{5}*40-\dfrac{1}{8}*40

Step 4: Simplify

40c=32-5

40c=27

Step 5: Divide both sides by 40 and simplify if possible.

c=\dfrac{27}{40}\\

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8 is not a factor of 36.... Your answer doesn't work.
m_a_m_a [10]
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Let f(x) represent a function.
STatiana [176]

Answer:

For f(x+\frac{5}{4}), f(x) is translated \frac{5}{4} units left.

For f(x)-\frac{5}{4}, f(x) is translated \frac{5}{4} units down.

Step-by-step explanation:

The transformation of f(x)\rightarrow f(x+C) means that the graph shift to left by C units if C is positive number and shifts to right by C units if C is a negative number.

The transformation of f(x)\rightarrow f(x)+C means that the graph shifts up by C units if C is positive number and shifts down by C units if C is a negative number.

Here, in the transformation of f(x)\rightarrow f(x+\frac{5}{4}),C = \frac{5}{4}>0, so, the function translates left by \frac{5}{4} units.

Similarly, in the transformation of f(x)\rightarrow f(x)-\frac{5}{4},C = -\frac{5}{4}, so, the function translates down by \frac{5}{4} units.

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3 years ago
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Answer:

C

Step-by-step explanation:

look up rules of multiplying radicals.

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