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4 years ago

It is warmer near the equator because that is where the Earth gets the most direct sunlight. T or f

Physics

2 answers:

Virty [35]4 years ago

7 0

This is true! The equator receives more sunlight than any other part of the earth so it is warmer!

Anni [7]4 years ago

4 0

True this is true bc yes as you said you're at the most direct point of sunlight

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Interactive Solution 28.5 illustrates one way to model this problem. A 7.11-kg object oscillates back and forth at the end of a

____ [38]

Explanation:

Given that,

Mass of the object, m = 7.11 kg

Spring constant of the spring, k = 61.6 N/m

Speed of the observer, $v=2.79\times 10^8\ m/s$

We need to find the time period of oscillation observed by the observed. The time period of oscillation is given by :

$t_o=2\pi \sqrt{\dfrac{m}{k}} \\\\t_o=2\pi \sqrt{\dfrac{7.11}{61.6}} \\\\t_o=2.13\ s$

Time period of oscillation measured by the observer is :

$t=\dfrac{t_o}{\sqrt{1-\dfrac{v^2}{c^2}} }\\\\t=\dfrac{2.13}{\sqrt{1-\dfrac{(2.79\times 10^8)^2}{(3\times 10^8)^2}} }\\\\t=5.79\ s$

So, the time period of oscillation measured by the observer is 5.79 seconds.

3 0

3 years ago

What happens when magma rises towards the surface?

zzz [600]

It slowly cools an hardens,eventually turning into igneous rock<span />

5 0

3 years ago

Read 2 more answers

A hollow spherical shell has mass 8.20 kg and radius 0.220 m. It is initially at rest and then rotates about a stationary axis t

Likurg_2 [28]

Answer:

8.91 J

Explanation:

mass, m = 8.20 kg

radius, r = 0.22 m

Moment of inertia of the shell, I = 2/3 mr^2

= 2/3 x 8.2 x 0.22 x 0.22 = 0.265 kgm^2

n = 6 revolutions

Angular displacement, θ = 6 x 2 x π = 37.68 rad

angular acceleration, α = 0.890 rad/s^2

initial angular velocity, ωo = 0 rad/s

Let the final angular velocity is ω.

Use third equation of motion

ω² = ωo² + 2αθ

ω² = 0 + 2 x 0.890 x 37.68

ω = 8.2 rad/s

Kinetic energy,

$K = \frac{1}{2}I\omega ^{2}$

K = 0.5 x 0.265 x 8.2 x 8.2

K = 8.91 J

6 0

3 years ago

A power cycle operates between a lake’s surface water at a temperature of 300 K and water at a depth whose temperature is 285 K.

nikdorinn [45]

Answer: a) 0.04kW = 40W

b) 0.05

Explanation:

Thermal efficiency of the power cycle = Input / output

Input = 10 kW + 14,400 kJ/min = 10 kW + 14,400 kJ/(60s) = 10 kW + 14,400/60 kW.

Output = 10 kW

Thermal Efficiency = Output / Input = 10kW / 250kW = 0.04KW = 40W

Maximum Thermal Efficiency of the power cycle = 1 - T1/T2

Where T1 = 285kelvin

And T2 = 300kelvin

Maximum Thermal Efficiency = 1 - T1/T2 = 1 - 285/300 = 0.05

8 0

4 years ago

Read 2 more answers

Galileo attempted to measure the speed of light by measuring the time elapsed between his opening a lantern and his seeing the l

Dafna11 [192]

Answer:

The distance is $2.58\times10^{7}\ m$ .

Explanation:

Given that,

Time $\Delta t = 0.2\ s$

The velocity is no more than a 14 % error in the speed of light.

So,

Velocity $v= c\times 86\%$

We need to calculate the distance

Using formula of speed

$v = \dfrac{d}{t}$

$d = v\times t$

Where, v = speed

d = distance

t = time

Put the value into the formula

$d = 3\times10^{8}\times\dfrac{86}{100}\times0.2$

$d=516\times10^{5}\ m$

We know that,

The one side distance d' is

$d'=\dfrac{d}{2}$

$d'=\dfrac{516\times10^{5}}{2}$

$d'=2.58\times10^{7}\ m$

Hence, The distance is $2.58\times10^{7}\ m$ .

5 0

3 years ago