We assign the variables: T as tension and x the angle of the string
The <span>centripetal acceleration is expressed as v²/r=4.87²/0.9 and (0.163x4.87²)/0.9 = </span><span>T+0.163gcosx, giving T=(0.163x4.87²)/0.9 – 0.163x9.8cosx.
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<span>(1)At the bottom of the circle x=π and T=(0.163x4.87²)/0.9 – .163*9.8cosπ=5.893N. </span>
<span>(2)Here x=π/2 and T=(0.163x4.87²)/0.9 – 0.163x9.8cosπ/2=4.295N. </span>
<span>(3)Here x=0 and T=(0.163x4.87²)/0.9 – 0.163x9.8cos0=2.698N. </span>
<span>(4)We have T=(0.163v²)/0.9 – 0.163x9.8cosx.
</span><span>This minimum v is obtained when T=0 </span><span>and v verifies (0.163xv²)/0.9 – 0.163x9.8=0, resulting to v=2.970 m/s.</span>
Answer:
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Answer:
235.8 N
Explanation:
Given that
Jack
83.5 east
Jill
93.3√2/2 east
93.3√2/2 north
Jane
121√2/2 east
121√2/2 south
From the above listed, we can calculate the total force component on x axis to be
Fx = 83.5 + 93.3√2/2 + 121√2/2
Fx = 83.5 + 65.97 + 85.56
Fx = 235 N (east)
Again, we calculate the total force component on y axis to be
Fy = 93.3√2/2 - 121√2/2
Fy = 65.97 - 85.56
Fy = -19.59 N (south)
Finding the resultant, we have
F = √(Fx²+Fy²)
F = √(235² + (-19.59)²)
F = √55225 + 383.7681
F = √55608.7681
F = 235.8 N
Explanation:
<h2>When we decrease the temperature, less heat energy is supplied to the atoms, and so their average kinetic energy decreases. When they enter a phase transition, such as freezing from a liquid to a solid, the temperature is not decreasing or increasing, and stays constant</h2>
Answer:
g = 15.5 m/s²
Explanation:
In order to find the acceleration due to gravity near the surface of this planet can be calculated by using 2nd equation of motion. The 2nd equation of motion is given as:
h = Vi t + (0.5)gt²
where,
h = height covered by the wrench = 5 m
Vi = Initial Velocity = 0 m/s
t = Time Taken to hit the ground = 0.804 s
g = acceleration due to gravity near the surface of the planet = ?
Therefore,
5 m = (0 m/s)(0.804 s) + (0.5)(g)(0.804 s)²
g = (5 m)/(0.3232 s²)
<u>g = 15.5 m/s²</u>
