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3 years ago

Please help have no clue on this

Physics

1 answer:

Nataliya [291]3 years ago

8 0

Has no effect on tempature

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Because atoms of elements in the same group of the periodic table have the same number of neutrons, they have similar properties

AURORKA [14]

False. What actually determines the properties of elements are the electrons, or aka valence electrons. They are used to bond, which determines its properties.

4 0

3 years ago

What best describes a sound wave? transverse and electromagnetic longitudinal and mechanical longitudinal and electromagnetic tr

GalinKa [24]

Sound needs medium to travel and it can not travel without medium

so sound wave is a travelling wave

now we also know that sound wave propagate in form of rarefaction and compression.

So all medium particles travel in the direction of wave only

so it is a longitudinal wave also

so correct answer will be

<em>mechanical longitudinal </em>

7 0

4 years ago

Read 2 more answers

Help ASAP!<br> Everything on screenshot

BARSIC [14]

Answer:

For the first one, its B) cities B and C

I'm not so sure, but I hope this helps.

7 0

3 years ago

The velocity of a body is increases from 10 m/s ti 15 m/s in 5seconds calculate its acceleration

Veseljchak [2.6K]

Answer:

acceleration = v-u/ t

= 15-10/5

= 5/5

= 1 m/s2

Explanation:

hope this helped you.

7 0

3 years ago

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A bowling ball that has a radius of 11.0 cm and a mass of 5.00 kg rolls without slipping on a level lane at 2.80 rad/s.

NemiM [27]

Answer:

$\dfrac{K_t}{K_r}=\dfrac{5}{2}$

Explanation:

Given that,

Mass of the bowling ball, m = 5 kg

Radius of the ball, r = 11 cm = 0.11 m

Angular velocity with which the ball rolls, $\omega=2.8\ rad/s$

To find,

The ratio of the translational kinetic energy to the rotational kinetic energy of the bowling ball.

Solution,

The translational kinetic energy of the ball is :

$K_t=\dfrac{1}{2}mv^2$

$K_t=\dfrac{1}{2}m(r\omega)^2$

$K_t=\dfrac{1}{2}\times 5\times (0.11\times 2.8)^2$

The rotational kinetic energy of the ball is :

$K_r=\dfrac{1}{2}I \omega^2$

$K_r=\dfrac{1}{2}\times \dfrac{2}{5}mr^2\times \omega^2$

$K_r=\dfrac{1}{2}\times \dfrac{2}{5}\times 5\times (0.11)^2\times (2.8)^2$

Ratio of translational to the rotational kinetic energy as :

$\dfrac{K_t}{K_r}=\dfrac{5}{2}$

So, the ratio of the translational kinetic energy to the rotational kinetic energy of the bowling ball is 5:2

4 0

3 years ago