$1;\ \frac{1}{32};\ \frac{1}{243};\ \frac{1}{1024};\ \frac{1}{3125}\\\\1=\frac{1}{1^5}\\\\\frac{1}{32}=\frac{1}{2^5}\\\\\frac{1}{243}=\frac{1}{3^5}\\\\\frac{1}{1024}=\frac{1}{4^5}\\\\\frac{1}{3125}=\frac{1}{5^5}\\\vdots\\\\a_n=\frac{1}{n^5}\ where\ n\in\mathbb{N^+}$

5 0

3 years ago

If you wish to calculate the interest on an investment with a rate of 6.17%, what number will you plug into your equation? a. 0.

sdas [7]

I think it’s answer B. Because % to decimal is 6.14% divided by 100 so the decimal would move to the left two places which in 0.0614

I now completely sure but I think that’s right

5 0

3 years ago

Read 2 more answers

HELP PLSSSSSSSSSSSSSSSSSSSSSSSS

velikii [3]

I would go withhh c but I am not 100% sure

6 0

2 years ago