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ivanzaharov [21]
3 years ago
11

\frac{11}{7} \div \frac{7}{10} " alt=" \frac{11}{7} \div \frac{7}{10} " align="absmiddle" class="latex-formula">
Please explain how to do this
Mathematics
2 answers:
MrRa [10]3 years ago
7 0
11/7 x 10/7= 110/49 is the answer to the question
AysviL [449]3 years ago
6 0

11/7÷7/10

=11/490

Hope this helps!

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Natalie picked 135 berries in 15 minutes. If she continues picking at that rate, how many total minutes will it take her to pick
Alex777 [14]
Lets focus on what we know first. Natalie can pick 135 Berries in 15 minutes. Lets find out how many berries she can pick per minute.
In order to do so, We have to divide 135 by 15.

135/15=9
This means that Natalie can pick 9 berries per minute. Given that we want her to pick 486, we will need to divide that number by 9 berries to find out how many minutes it will take to get her to that number of berries.

486/9=54

This means that it will take Natalie 54 minutes in order to pick 486 berries. 
5 0
3 years ago
Write an expression with a negative exponent that has a value between 0 and 1:2
Naddika [18.5K]
Edit to reflect comments:

3^-1=1/3
4^-1=1/4

Flip the fraction over basically i.e. 4/1---->1/4
7 0
3 years ago
What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu
inn [45]

Answer:

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Step-by-step explanation:

The given expression is

\frac{2x+5}{x^{2} -3x} -\frac{3x+5}{x^{3} -9x} -\frac{x+1}{x^{2}-9}

First, we need to factor each denominator

\frac{2x+5}{x(x-3)} -\frac{3x+5}{x(x+3)(x-3)} -\frac{x+1}{(x-3)(x+3)}

So, the least common factor (LCF) is x(x-3)(x+3), because they are the factors that repeats.

Now, we diviide the LCF by each denominator, to then multiply it by each numerator.

\frac{(x+3)(2x+5)-3x-5-x(x+1)}{x(x-3)(x+3)} =\frac{2x^{2}+5x+6x+15-3x-5-x^{2}-x }{x(x-3)(x+3)}\\\frac{x^{2}+7x+10}{x(x-3)(x+3)}

Then, we factor the numerator, to do so, we need to find two numbers which product is 10 and which sum is 7.

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Therefore, the expression is equivalent to

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

8 0
2 years ago
Read 2 more answers
Rotate the point A (-3,4) 270°about the origin. Plot A' on the grid.
koban [17]

Answer:

Step-by-step explanation:

it should be (3,4) if not im srry

7 0
3 years ago
What is an equivalent function to f(x)=(x-2)^3
atroni [7]

Answer:

x^3-6x^2-4x-8

Step-by-step explanation:

First you would multiply (x-2) by itself (x-2) to get

x^2-2x-2x+4

then you would combine like terms

x^2-4x+4

Then you would multiply that by x-2

(x^2-4x+4)(x-2)

x^3-2x^2-4x^2-8x+4x-8

then you combine like terms

x^3-6x^2-4x-8

3 0
3 years ago
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