Let the lengths of pregnancies be X
X follows normal distribution with mean 268 and standard deviation 15 days
z=(X-269)/15
a. P(X>308)
z=(308-269)/15=2.6
thus:
P(X>308)=P(z>2.6)
=1-0.995
=0.005
b] Given that if the length of pregnancy is in lowest is 44%, then the baby is premature. We need to find the length that separates the premature babies from those who are not premature.
P(X<x)=0.44
P(Z<z)=0.44
z=-0.15
thus the value of x will be found as follows:
-0.05=(x-269)/15
-0.05(15)=x-269
-0.75=x-269
x=-0.75+269
x=268.78
The length that separates premature babies from those who are not premature is 268.78 days
3'=3*12=36"
2'=2*12=24"
Area = 36" * 24" = 864 sq. in.
Answer:
See below
Step-by-step explanation:
The difference of 5 and 2
5-2 <===== now multply it by 6
6 x (5-2)
0 I think hope it’s right
Answer:
$ 190
Step-by-step explanation:
To find the answer you add $112.65 , $29.75 and $48.33.
The answer then becomes $190.73
That means approximetely he spent because $ 190 is closer to $190.73 than $170 , $210 and $ 230.
answer is $190
HOPE THIS HELPED
