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slava [35]
3 years ago
15

What is the sum of the two vectors (2,-1) and (3,3)?

Mathematics
2 answers:
suter [353]3 years ago
8 0
(5,2)is the answer to this question
vagabundo [1.1K]3 years ago
6 0
Answer: (5, 2)

We simply add up the corresponding coordinates. The x coordinates of the two vectors are 2 and 3. They add to 2+3 = 5

The y coordinates are -1 and 3. They add to -1+3 = 2

So overall, 
(2,-1) + (3,3) = (2+3, -1+3) = (5,2)
is the answer
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What is the GCF of 6 and 36
Tresset [83]

Answer:

It's 6.

Step-by-step explanation:

6- 1, 2, 3, <u>6</u>

36- 1, 2, 3, 4, <u>6</u>

5 0
2 years ago
Mickey said that 45.7654 rounded to the nearest thousandth is 45.765 and Nicole said that it was 45.766. Who is correct and why?
Nesterboy [21]

Answer:

Mickey

Step-by-step explanation:

Mickey is correct because if you look at the number 45.7654 whenever you round to the nearest thousandth it'll be 45.765

5 is the thousandth place so look to the right. If the number to the right is greater than 5 it'll round to 47.766 but since it's a four ti rounds down.

8 0
2 years ago
Read 2 more answers
Pls help this is major, ill mark u brainliest
Lera25 [3.4K]

Answer:

105

Step-by-step explanation:

A=lw   A=(.5)πr²

to get the area of the shaded parts you have to subtract the area of the semicircle from the area of the rectangle

A=(16)(9)

A=144

A=\frac{(3.14)(5)^2}{2} A=\frac{(3.14)(25)}{2} A=\frac{78.5}{2}

A=39.25

subtract the areas

144-39.25=104.75

104.75 ≅ 105

4 0
2 years ago
Are 27 49 57 63 composite numbers
Helen [10]
Yes they are 
Composite numbers <span />
7 0
2 years ago
Read 2 more answers
Simplify 4n5 + 3.5n5 + (-2.1n5).<br><br> 4.4 n5<br> 5.4 n5<br> 20 n5<br> 6.4 n5
ella [17]

Answer:

4 {n}^{5}  + 3.5 {n}^{5}  + ( - 2.1 {n}^{5} )

first create a bracket:

= ( {4n}^{5}  + 3.5 {n}^{5} ) + ( - 2.1 {n}^{5} )

then solve the first bracket:

=  {7.5 {n}^{5} } + ( - 2.1 {n}^{5} )

then open the remaining bracket:

=  {7.5n}^{5}  -  {2.1n}^{5}

carryout the subtraction operation:

= (7.5 - 2.1) {n}^{5}  \\ { \boxed{ =  {5.4n}^{5} }}

7 0
3 years ago
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