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Maurinko [17]
3 years ago
5

If you find that the hydrogen alpha line in a star’s spectrum occurs at a wavelength of 656.45 nm, what is the star’s approximat

e radial velocity? Note that the rest wavelength of this line is 656.30 nm.
Chemistry
1 answer:
Paladinen [302]3 years ago
8 0

Answer:

The answer to the question is

The star’s approximate radial velocity is 68.52 km/s

Explanation:

To solve the

The formula is

\frac{\lambda-\lambda_{rw}}{\lambda_{rw}} = \frac{v_r}{c} where

v_r = velocity of the star

λ = Star's spectrum wavelength = 656.45 nm

\lambda_{rw} = Rest wavelength = 656.30 nm

c = Speed of light = 299 792 458 m / s

Therefore we have

\frac{656.45-656.30}{656.30} =\frac{v_r}{299 792 458} or v_r = 68518.7699 m/s or 68.52 km/s

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Explanation:

Hello,

In this case, considering that the density is considered as the quotient of the mass and volume:

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