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3 years ago

14

If the density of a metal bar is 3.47 g/mL and volume is 30 mL, calculate the mass of the metal bar in grams (g). Show the steps

to answering this equation.

1 answer:

Hitman42 [59]3 years ago

7 0

Answer:

$m=104.1g$

Explanation:

Hello,

In this case, considering that the density is considered as the quotient of the mass and volume:

$\rho =\frac{m}{V}$

We can easily compute the mass by solving for it as follows:

$m=V*\rho =30 mL*3.47g/mL\\\\m=104.1g$

Best regards.

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$c_1$ = specific heat of calorimeter = $12.1J/^oC$

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$m_2$ = mass of water or solution = $Density\times Volume=1/mL\times 100.0mL=100.0g$

$\Delta T$ = change in temperature = $T_2-T_1=(26.3-20.2)^oC=6.1^oC$

Now put all the given values in the above formula, we get:

$q=[(12.1J/^oC\times 6.1^oC)+(100.0g\times 4.18J/g^oC\times 6.1^oC)]$

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Now we have to calculate the enthalpy change for the process.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

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$\Delta H=\frac{2623.61J}{0.050mole}=52472.2J/mole=52.5kJ/mole$

Therefore, the enthalpy change for the process is 52.5 kJ/mole.

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