A bus manufacturer decides to double a window's area in order to give passengers a

A proton is accelerated down a uniform electric field of 450 N/C. Calculate the acceleration of this proton.

olasank [31]

Answer:

The acceleration of proton will be $431.137\times 10^8m/sec^2$

Explanation:

We have given electric field E = 450 N/C

Charge on proton $=1.6\times 10^{-19}C$

Force on electron due to electric field is given by $F=qE=1.6\times 10^{-19}\times 450=720\times 10^{-19}N$

Mass of electron $m=1.67\times 10^{-27}kg$

Now according to second law of motion $F=ma$

So $720\times10^{-19}=1.67\times 10^{-27}a$

$a=431.137\times 10^8m/sec^2$

So the acceleration of proton will be $431.137\times 10^8m/sec^2$

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3 years ago

Explain why an object’s weight is dependent upon where in the universe it is located.

strojnjashka [21]

Answer:

The weight of any object will depend on its location in the universe, commanded by the law of gravitacion universal de Newton

Explanation:

Everything obeys the law of universal gravity proposed by Newton. Where the attraction force with which one body attracts another depends on the mass of the body that attracts the body with less mass, the radius of the body with the greatest mass and the universal gravitational constant.

For a better understanding of this concept let us use examples with numeric values. In the first example we will determine with what force planet Earth attracts a person of 70 [kg].

And in the second example we will perform the same exercise but on a planet like Jupiter

Example 1:

A person with a mass of 70 [kg] is located on planet Earth which has a mass of 5.97x10^24 [kg] and a terrestrial radius of 6371 [km]. Find the force exerted by the planet upon the person.

We have the law of universal gravity

$F=G*\frac{m_{1} *m_{2} }{r^{2} } \\where\\G = 6.67*10^-11[\frac{N*m^{2} }{kg^{2}} ]\\m_{1}=70[kg]\\m_{2}=5.97*10^{24} [kg]\\r= 6371[km]$

Now replacing the values in the equation we have:

$F=6.67*10^{-11} *\frac{70*5.97*10^{24} }{(6371*10^3)^{2} } \\F=687[N]$

We can appreciate that if we only use the terms of mass of the earth, the gravitational constant and the radius of the earth, we will have the value of the gravity accelaration of the earth. Let's check

$g_{earth} =6.67*10^{-11} *\frac{5.97*10^{24} }{(6371*10^3)^{2} } \\g_{earth} = 9.81 [m/s^{2} ]$

Example 2:

A person with a mass of 70 [kg] is located on planet Jupiter which has a mass of 1.899x10^27 [kg] and a radius of 71492 [km]. Find the force exerted by the planet upon the person.

$F=6.67*10^{-11}*\frac{70*1.899*10^{27} }{(71492*10^3)^{2} } \\F= 1734.73[N]$

We will calculate the value of the gravity accelaration of Jupiter. Let's check

$g_{jupiter} = 6.67*10^{-11} *\frac{1.899*10^{27} }{(71492*10^3)^{2} } \\g_{jupiter}= 24.8 [m/s^2]\\$

Therefore an object in jupiter will weigh more than 2.5 times its weight than on planet Earth.

We found that the force of attraction or the weight of any object will depend on its location in the universe, commanded by the law of gravitacion universal de Newton

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3 years ago

How can one explain the fact that nearly all other galaxies appear to be moving farther away from us?

juin [17]

A) the universe is expanding
Every galaxy is moving away from each other - not just us. And the further they are away, the faster they are moving

4 0

2 years ago

Read 2 more answers

When the temperature of a gas in a balloon is reduced by half, the average kinetic energy of the particles is

Aneli [31]

According to KE = (3/2)kT

reducing temperature, in KELVIN, by half, average KE is reduced by half.

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