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docker41 [41]
3 years ago
13

Describe how phospholipids form a barrier between water inside the cell and water outside the cell

Chemistry
1 answer:
Lynna [10]3 years ago
6 0
<span>Phospholipids would have to form a phospholipid bilayer in order to achieve water on the outside and water inside. This is because the nonpolar tails of the phospholipids are facing each other in a water environment because they cannot interact with the water, only their own tails, while the phosphate heads of the molecule face the periphery of the tails and interact with water. Micelles are the simplest examples of these.</span>
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Part a cyclohexane has a freezing point of 6.50 ∘c and a kf of 20.0 ∘c/m. What is the freezing point of a solution made by disso
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The mathematical expression for the depression in freezing point is given as:

\Delta T_{f}= k_{f}m

where, \Delta T_{f} = depression in freezing point

k_{f} = molal depression constant    (20.0 ^{o}Ckg/mole)

m = molality

Molality is defined as the ratio of number of moles of solute to the kg of the solvent

Number of moles  =\frac{given mass in g}{molar mass}

given mass  of biphenyl solute = 0.925 g

Molar mass of biphenyl  = 154.21 g/mol

Put the values,

number of moles of biphenyl =\frac{0.925 g}{154.21 g/mol}

= 0.0059 mole

Molality =\frac{number of moles of biphenyl solute}{mass of the solvent in kg}

Mass of cyclohexane solvent  = 25.0 g

Convert g into kg: 1 kg = 1000 g

Thus, mass of cyclohexane  = \frac{25.0}{1000}

= 0.025 kg

Now, put the values in the formula of molality:

Molality =\frac{0.0059 mole}{0.025 kg}

= 0.236 mole/kg or 0.236 m.

Calculate the depression in freezing point:

\Delta T_{f}= 20.0^{o}C kg/mole\times 0.236 mole/kg

= 4.72 ^{o}C

Now, \Delta T_{f} = T_{solvent} - T_{solution}

4.72 ^{o}C = 6.50^{o}C - T_{solution}

T_{solution} = 6.50^{o}C- 4.72 ^{o}C

= 1.78^{o}C

Hence, freezing point of the solution is 1.78^{o}C.



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