Answer:
The molar mass of the compound given is 182.182 g/mol.
Explanation:
To calculate the molar mass of the compound, we must multiply the number of moles of each element by the the individual molar mass of each element and add them together.
Let's start with Calcium. The molar mass of Calcium is 40.078. In this compound, we have three moles of Calcium, so we should multiply this number by 3.
40.078 g/mol * 3 mol = 120.234 g
Now, let's do the same for Phosphorus.
30.974 g/mol * 2 g/mol = 61.948 g
To find the molar mass of the entire compound, we should add these two values together.
120.234 g + 61.948 g = 182.182 g
Therefore, the correct answer is 182.182 g/mol.
Hope this helps!
The empirical and molecular formula : C₂₁H₂₂N₂O₂
<h3>Further explanation</h3>
Given
The percent composition of an unknown substance is 75.42% Carbon, 6.63 % Hydrogen,
8.38 % Nitrogen, and 9.57 % Oxygen
Required
The empirical and molecular formula
Solution
C : 75.42 : 12 = 6.285
H : 6.63 : 1 = 6.63
N : 8.38 : 14 = 0.599
O : 9.57 : 16 = 0.598
Divide by 0.598
C : H : N : O = 10.5 : 11 : 1 : 1 = 21 : 22 : 2 : 2
The empirical formula : C₂₁H₂₂N₂O₂
(C₂₁H₂₂N₂O₂)n = 334
(334)n=334
n = 1
Combustion! CH4, which is methane, reacts with oxygen to form carbon dioxide. (For future reference, if a compound is reacted with ONLY oxygen it is sure to be a combustion reaction)
Calcium carbonate will be formed which is insoluble in water.
The answer is a) K and CrO4 only.
