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3 years ago

Triangle AB is 15 BD 9 what is area ABC

Mathematics

2 answers:

PIT_PIT [208]3 years ago

7 0

Answer:

Area of the triangle = <em>67.5 sq.units</em>

Step-by-step explanation:

here's the solution : -

in the given triangle,

AB is base and BD is height ( perpendicular )

Area of a triangle =

$\frac{1}{2} \times base \: \times height$

=》

$\frac{1}{2} \times 15 \times 9$

=》

$\frac{1}{2} \times 135$

=》

$67.5$

Area of the triangle = 67.5 sq.units

krek1111 [17]3 years ago

3 0

Answer:

it is your answer...... if it is helpful plzz like ans comment

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16x72(192/13) please help me solve this

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4 years ago

Read 2 more answers

The value of the 4 in 429?

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Answer: It is in the Hundreds place

Step-by-step explanation:

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3 years ago

Penelope made note of all the bicycles and cars she could see parked or locked on acertain city block. All the cars had exactly

lesantik [10]

Given:

The number of cycles is, <em>n</em> (s) = 7.

The number of wheels in the cycle is, <em>n </em>(sw) = 2.

The number of cars is, <em>n</em> (c) = 15.

The number of wheels in the car is, <em>n</em> (cw) = 4.

The obective is to find the total number of wheels.

The total number of wheels is,

$\begin{gathered} T=n(sw)\cdot n(s)+n(cw)\cdot n(c) \\ =2\cdot7+4\cdot15 \\ =14+60 \\ =74\text{ whe}els \end{gathered}$

Hence, there are 74 wheels in the block.

If there are <em>x</em> bicycles and <em>y </em>cars, the equatioin will be,

$\begin{gathered} T=n(sw)\cdot x+n(ce)\cdot15 \\ T=2x+4x \end{gathered}$

Hence, the number of wheels for x bicycles and y cars is 2x+4x.

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1 year ago

The formula for finding the perimeter of a rectangle is P = 2L + 2W. If a rectangle has a perimeter of 68 inches and the length

Artemon [7]

Answer:

Width = 10 inches

Step-by-step explanation:

Given the perimeter of a rectangle of 68 inches, and a length that is 14 inches longer than its width.

We can establish the following values to help us solve for the width of a rectangle:

Perimeter (P) = 68 inches

Length (L) = 14 + W inches

Width (W) = unknown

<h3 /><h3><u>Solve for the Width (W)</u></h3>

P = 2(L + W) ⇒ This is the same as P = 2L + 2W, except that 2 is factored out from the right-hand side.

Divide both sides by 2:

$\displaystyle\mathsf{\frac{P}{2}\:=\:\frac{2(L\:+\:W)}{2}}$

$\displaystyle\mathsf{\frac{P}{2}\:=L\:+\:W}$

Substitute the value of the Perimeter and the length (L) into the formula:

$\displaystyle\mathsf{\frac{68}{2}\:=14\:+W\:+\:W}$

Combine like terms on the right-hand side, and simplify the left-hand side of the equation:

$\displaystyle\mathsf{34\:=14\:+2W}$

Subtract 14 from both sides:

34 - 14 = 14 - 14 + 2W

20 = 2W

Divide both sides by 2 to solve for the width (W):

$\displaystyle\mathsf{\frac{20}{2}\:=\:\frac{2W}{2}}$

W = 10 inches

Therefore, the width of the rectangle is 10 inches.

<h3 /><h3><u>Double-check:</u></h3>

Verify whether the derived value for the width is correct:

P = 2L + 2W

68 = 2(14 + 10) + 2(10)

68 = 2(34) + 20

68 = 48 + 20

68 = 68 (True statement).

Thus, the length of the rectangle is 34 inches, and the width is 10 inches.

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3 years ago