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amm1812
3 years ago
7

Solve for x. 5(х – 10) = 30 — 15х x = 1 x = 4 х = 5 х = 8

Mathematics
1 answer:
Sever21 [200]3 years ago
8 0

In order to solve for x, we must do the following:

5(x - 10) = 30 - 15x

5x - 50 = 30 - 15x (Expand 5(x - 10) )

5x - 50 + 50 = 30 - 15x + 50 (Add 50 to both sides of the equation)

5x = 80 - 15x

5x + 15x = 80 - 15x + 15x (Add 15x to both sides)

20x = 80

20x/20 = 80/20 (Divide both sides by 20)

x = 4

Therefor, the correct answer is the second option (x = 4).

You can always check if this is correct by substituting your answer back into the original equation and seeing if the left side is equal to the right side (this is also a potential method for solving the question itself if it is multiple choice, but I find it is often better to actually solve the equation rather than substitute each answer to see which works):

5(x - 10) = 30 - 15x

if x = 4:

5(4 - 10) = 30 - 15(4)

5(-6) = 30 - 60

-30 = -30

The two sides are equal, therefor x = 4 is confirmed as the correct answer.

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5z3 - 224 - 9z2 + 2<br> What is the degree of the polynomial?<br> I
hoa [83]

Answer:

5{z}^{3}-222-9{z}^{2}5z

​3

​​ −222−9z

​2

Step-by-step explanation:

1 Collect like terms.

5{z}^{3}+(-224+2)-9{z}^{2}5z

​3

​​ +(−224+2)−9z

​2

​​  

2 Simplify.

5{z}^{3}-222-9{z}^{2}5z

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Done

7 0
3 years ago
The lines are parallel. Find the slope-intercept form of the equation y₂.
Bas_tet [7]
Since the lines are parallel and you know the slope of y_{1} is -2, you know the slope of line y_{2} will also be -2. You can see on the coordinate grid that line y_{2} crosses the y-axis at -1. When you piece all of these facts together into slope-intercept form you get y_{2} = -2x - 1.
6 0
3 years ago
The solution to a quadric equation are x=2 and x=7. If k is a nonzero constant which of the following must be equal to the quadr
nikklg [1K]

Answer:

The quadratic equation form is x² - 9 x + 14  = 0            

Step-by-step explanation:

Given in the question as ,

The solution of quadratic equation are x = 2   and x = 7

The constant K is a non-zero number

Now , let the quadratic equation be , ax² + bx + c = 0

And  sum of roots = \frac{ - b}{a}

       product of roots = \frac{c}{a}

So, 2 + 7 = \frac{ - b}{a}

Or, 2 × 7 =  \frac{c}{a}

I.e \frac{ - b}{a}  = 9     ,     \frac{c}{a} = 14

Or,  b =  - 9 a           And c = 14 a

Put this value of b and c in standard form of quadratic equation

I.e ax² + bx + c = 0

Or, ax² - 9 ax + 14 a = 0

Or , a ( x² - 9 x + 14 ) = 0  

∴ a = 0   And  x² - 9 x + 14 = 0

Hence ,  The quadratic equation form is x² - 9 x + 14  = 0      Answer

7 0
3 years ago
3. A submarine dives at an
Vesna [10]

Answer:

The height of deepness of submarine is 424.1 feet  

Step-by-step explanation:

Given as :

The angle at which submarine drives of the surface of water = Ф = 13°

The speed at which submarine travel = s = 760 feet per minute

Let The height of deepness of submarine = h feet

The time taken to reach that deepness = t = 5 minutes

<u>According to question</u>

The height of deepness of submarine = \dfrac{\textrm speed}{\textrm time}

i.e h × cos(90 - Ф) = \dfrac{s}{t}

Or,  h × Sin(Ф) = \dfrac{\textrm 760 feet per min}{8 min}

Or,  h × Sin(13°) = 95 feet

Or,   h × 0.224 = 95 feet

∴  h = \dfrac{95}{0.224}

i.e h = 424.10 feet

So, The height of deepness of submarine = h = 424.10 feet

Hence, The height of deepness of submarine is 424.1 feet  Answer

8 0
3 years ago
Pre-algebra slope equation . Helps plz Only one problem Thankss !
Allushta [10]
Y + 4 = -4 (x - 6) ...point slope equation form

hope it helps
4 0
3 years ago
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