Answer:
5{z}^{3}-222-9{z}^{2}5z
3
−222−9z
2
Step-by-step explanation:
1 Collect like terms.
5{z}^{3}+(-224+2)-9{z}^{2}5z
3
+(−224+2)−9z
2
2 Simplify.
5{z}^{3}-222-9{z}^{2}5z
3
−222−9z
2
Done
Since the lines are parallel and you know the slope of

is -2, you know the slope of line

will also be -2. You can see on the coordinate grid that line

crosses the y-axis at -1. When you piece all of these facts together into slope-intercept form you get
= -2x - 1.
Answer:
The quadratic equation form is x² - 9 x + 14 = 0
Step-by-step explanation:
Given in the question as ,
The solution of quadratic equation are x = 2 and x = 7
The constant K is a non-zero number
Now , let the quadratic equation be , ax² + bx + c = 0
And sum of roots = 
product of roots = 
So, 2 + 7 =
Or, 2 × 7 = 
I.e
= 9 ,
= 14
Or, b = - 9 a And c = 14 a
Put this value of b and c in standard form of quadratic equation
I.e ax² + bx + c = 0
Or, ax² - 9 ax + 14 a = 0
Or , a ( x² - 9 x + 14 ) = 0
∴ a = 0 And x² - 9 x + 14 = 0
Hence , The quadratic equation form is x² - 9 x + 14 = 0 Answer
Answer:
The height of deepness of submarine is 424.1 feet
Step-by-step explanation:
Given as :
The angle at which submarine drives of the surface of water = Ф = 13°
The speed at which submarine travel = s = 760 feet per minute
Let The height of deepness of submarine = h feet
The time taken to reach that deepness = t = 5 minutes
<u>According to question</u>
The height of deepness of submarine = 
i.e h × cos(90 - Ф) = 
Or, h × Sin(Ф) = 
Or, h × Sin(13°) = 95 feet
Or, h × 0.224 = 95 feet
∴ h = 
i.e h = 424.10 feet
So, The height of deepness of submarine = h = 424.10 feet
Hence, The height of deepness of submarine is 424.1 feet Answer
Y + 4 = -4 (x - 6) ...point slope equation form
hope it helps