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3 years ago

Copper (II) nitrate, Cu(NO3)2, solution reacts with potassium hydroxide, KOH, to form a blue

Chemistry

1 answer:

Gekata [30.6K]3 years ago

6 0

Answer:

Copper(II) nitrate and potassium hydroxide are soluble ionic compounds, which implies that they dissociate completely when dissolved in water to produce ions. ... You can thus say that the balanced chemical equation that describes this double ... Cu(NO3)2(aq)+2KOH(aq)→Cu(OH)2(s)⏐⏐↓+2KNO3(aq).

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Lithium has the electron arrangement 2,1. When lithium forms an ion,

iragen [17]

Answer:

when lithium forms an ion it donates 1 electron

which makes its electron configuration to become 2

4 0

3 years ago

Nancy and Hiyang are training for a race. They entered some of their training notes in a chart. Which information should be adde

Mnenie [13.5K]

The information that should be added to the chart in order to find out who ran a greater distance is THE UNITS USED TO MEASURE DISTANCE EACH DAY.

In science, the use of units if very important and each record made must be accompany with relevant units that are appropriate for the measurement taken. If units are not used along with data, it will be very difficult to quantify the values that are recorded. Scientists all over the world use SI units in their works in order to ensure uniformity.

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3 years ago

Read 2 more answers

If a rock had a mass of 20g explain how you would fund the density

REY [17]

Answer:

you have to divide it

Explanation:

4 0

2 years ago

Read 2 more answers

A beaker with 1.60×102 mL of an acetic acid buffer with a pH of 5.000 is sitting on a benchtop. The total molarity of acid and c

stich3 [128]

Answer:

The pH will change 0.16 ( from 5.00 to 4.84)

Explanation:

Step 1: Data given

volume of acetic acid buffer = 160 mL

The total molarity of acid and conjugate base in this buffer is 0.100 M

A student adds 7.10 mL of a 0.460 M HCl solution to the beaker.

The pKa of acetic acid is 4.740

pH = 5.00

Step 2: Calculate concentration of acid

Consider x = concentration acid

Consider y = concentration conjugate base

x + y = 0.100

5.00 = 4.740 + log y/x

5.00 - 4.740 = log y/x

0.26 = log y/x

10^0.26 =1.82 = y/x

1.82 x = y

Since x+y = 0.100

x + 1.82 x = 0.100

2.82 x = 0.100

x =0.0355 M = concentration acid

Step 3: Calculate concentration of conjugate base

y = 0.100 - x

0.100 - 0.0355 =0.0645 M= concentration conjugate base

Step 4: Calculate moles of acid

Moles = volume * molarity

moles acid = 0.160 L * 0.0355 M= 0.00568 moles

Step 5: Calculate moles of conjugate base

moles conjugate base = 0.0645 M * 0.160 L=0.01032 moles

Step 6: Calculate moles HCl

moles HCl = 7.10 * 10^-3 L * 0.460 M=0.003266 moles

Step 7: Calculate new moles

A- + H+ = HA

moles conjugate base = 0.01032 - 0.003266 =0.007054 moles

moles acid = 0.00568 + 0.003266=0.008946 moles

Step 8: Calculate the total volume

total volume = 160 + 7.10 = 167.1 mL = 0.1671 L

Step 9: Calculate the concentration of the acid

concentration acid = 0.008946/ 0.1671 =0.0535 M

Step 10: Calculate the concentration of conjugate base

concentration conjugate base = 0.007054/ 0.1671 =0.0422 M

Step 11: Calculate the pH

pH = 4.740 + log 0.0535/ 0.0422=4.84

change pH = 5.00 - 4.84=0.16

The pH will change 0.16

5 0

3 years ago

Using a value of Ksp = 1.8 x 10-2 for the reaction PbCl2 Pb+2(aq) + 2Cl -(aq). If the value of Ksp was determined to be only 1.2

ohaa [14]

Answer:

The correct answer is option D, that is, the ions are now combining to reduce their concentrations.

Explanation:

On the basis of the chemical equation:

PbCl₂ (s) ⇒ Pb²⁺ (aq) + 2Cl⁻ (aq)

It is mentioned that the value of Ksp is 1.8 × 10⁻²

As the solubility product is very less or negligible for this reaction that signifies that the ions produced are getting combined, resulting in the reduction of the concentration of the ions and enhancing the formation of the solid lead chloride. Therefore, they associate together to produce solid lead chloride.

4 0

2 years ago