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Leya [2.2K]
3 years ago
14

Which is a cause of physical weathering but not of chemical weathering ??

Chemistry
1 answer:
Soloha48 [4]3 years ago
8 0
Wind becuase you can feel it whhich is physical 

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For a trip to the Moon, a rocket must lift off from
VLD [36.1K]

Answer:

20 m/s^2

Explanation:

given,

final velocity (v) = 6000m/s

initial velocity (u) = 0m/s

time taken (t) = 5 minutes

= 5×60second

= 300second

acceleration(a) = ?

we know that,

a = (v-u)/t

= (6000-0)/300

= 20 m/s^2

5 0
3 years ago
Which of the following is NOT soluble in water?
GrogVix [38]
C6H6 is the most insoluble in water as it is non polar in nature. HCL is highly soluble in water as it is an electrolyte. Kbr is also highly soluble in water. NaCl dissolves in water very quickly. CH3CH3OH is also totally soluble in water because of the Hydrogen bonding formation. It is a well known fact that the hydrocarbons do not easily mix with water. C6H6 being a strong hydrocarbon does not mix with water. So among NaCl, KBr, CH3CH3OH, HCl and C6H6, the hydrocarbon is the least soluble in water.


5 0
3 years ago
A gas has a pressure of 1.34 atm when the temperature is 237K. The gas is then heated until the temperature measures 312K. What
alexandr1967 [171]

The answer for the following question is answered below.

  • <em><u>Therefore the new pressure of the gas is 1.76 atm.</u></em>

Explanation:

Given:

Initial pressure of the gas = 1.34 atm

Initial temperature of the gas = 273 K

final temperature of the gas = 312 K

To solve:

Final temperature of the gas

We know;

From the ideal gas equation

P × V = n × R × T

So;

from the above equation we can say that

    <em>P ∝ T</em>

     \frac{P}{T} = constant  

     \frac{P_{1} }{P_{2} } = \frac{T_{1} }{T_{2} }

Where;

P_{1} = initial pressure of a gas

P_{2} = final pressure of a gas

T_{1} = initial temperature of a gas

T_{2} = final temperature of  a gas

    P_{2} = \frac{1.34*312}{237}

    P_{2}  = 1.76 atm

<em><u>Therefore the new pressure of the gas is 1.76 atm.</u></em>

6 0
3 years ago
Fill in the coefficients, help, please.
Y_Kistochka [10]
1,2,1,4 are your coefficients
3 0
3 years ago
A 3.90L sample of gas at STP is cooled to -55oC at 808mmHg. What is the new volume?
notsponge [240]

Answer:

3.72L

Explanation:

Given parameters:

Initial volume V₁ = 3.9L

Condition  = STP

Final temperature T₂ = -550°C

Final pressure P₂  = 880mmHg

Unknown:

Final volume V₂  = ?

Solution.

At standard temperature and pressure(STP), the:

           Pressure  = 1atm   = 760mmHg

            Temperature  = 273K

Therefore, P₁  = 760mmHg

                  T₁  = 273K

The general gas law, is best to solve this problem. It is mathematically given as:

           \frac{P_{1} V_{1} }{T_{1} }   = \frac{P_{2} V_{2} }{T_{2} }

Let us take the units to the appropriate one;

      -550°C  = 273 + (-550) = -277K

Input the variables;

             \frac{760 x 3.9}{273}  = \frac{808 x V_{2} }{-277}

        V₂  = 3.72L

           

5 0
3 years ago
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