Compare the density of the rubber to water. If it is less that 1 g/mL then it floats in the water.
You must compare density in the same units. So convert to g/mL
The rubber does not float in water.
Answer: 401.4g
Explanation:
The mass can be calculated by using the following mathematical expression for Moles ,which is:
Moles = Mass / Molar Mass
From the question given, Moles = 1.72, Molar mass of BaSO4 = 233.38g/mol, Mass =?
Making 'Mass' the subject of formula, we get:
Mass = Molar mass x Moles
= 233.38 x 1.72 = 401.4g
Answer:
C is the only reasonable answer.. but this is 6th grade science and I'm in 7th, so I'm pretty sure I'm right
Answer:
For a fixed mass of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional. Or Boyle's law is a gas law, stating that the pressure and volume of a gas have an inverse relationship. If volume increases, then pressure decreases and vice versa, when the temperature is held constant..
Explanation:
Hope it helps you..
Y-your welcome in advance..
(;ŏ﹏ŏ)(ㆁωㆁ)
Missing question:
A. [3.40 mol Fe2O3 (s) × 26.3 kJ/1 mol Fe2O3 (s)] / 2
<span>B. 3.40 mol Fe2O3 (s) × 26.3 kJ/1 mol Fe2O3 (s) </span>
<span>C. 26.3 kJ/1 mol Fe2O3 (s) / 3.40 mol Fe2O3 (s) </span>
<span>D. 26.3 kJ/1 mol Fe2O3 (s) – 3.40 mol Fe2O3 (s).
</span>Answer is: B.
Chemical reaction: F<span>e</span>₂O₃<span>(s) + 3CO(g) → 2Fe(s) + 3CO</span>₂<span>(g);</span>ΔH = <span>+ 26.3 kJ.
When one mole of iron(III) oxide reacts 26,3 kJ of energy is required and for 3,2 moles of iron(III) oxide 3,2 times more energy is required.</span>
