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mr Goodwill [35]
3 years ago
13

18°C = _____ -255 K 0 K 18 K 291 K

Chemistry
2 answers:
horrorfan [7]3 years ago
7 0
T K = ºC + 273

T = 18 + 273

T = 291 K

hope this  helps!
g100num [7]3 years ago
3 0

Answer:

T = 291 K

Explanation:

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Calculate the pH at of a 0.10 Msolution of anilinium chloride . Note that aniline is a weak base with a of . Round your answer t
notsponge [240]

The question is incomplete, here is the complete question:

Calculate the pH at of a 0.10 M solution of anilinium chloride (C_6H_5NH_3Cl) . Note that aniline (C6H5NH2) is a weak base with a pK_b of 4.87. Round your answer to 1 decimal place.

<u>Answer:</u> The pH of the solution is 5.1

<u>Explanation:</u>

Anilinium chloride is the salt formed by the combination of a weak base (aniline) and a strong acid (HCl).

To calculate the pH of the solution, we use the equation:

pH=7-\frac{1}{2}[pK_b+\log C]

where,

pK_b = negative logarithm of weak base which is aniline = 4.87

C = concentration of the salt = 0.10 M

Putting values in above equation, we get:

pH=7-\frac{1}{2}[4.87+\log (0.10)]\\\\pH=5.06=5.1

Hence, the pH of the solution is 5.1

8 0
3 years ago
Which one of the following sets of units is appropriate for a second-order rate constant?
Natalija [7]

Answer:

C. L mol-1 s-1.

Explanation:

Hello,

In this case, a rate law has the following general form:

r=kC^x_i

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In such a way, since in this case x equals two (second-order rate), the units of k turns out:

\frac{M}{s}=\frac{mol}{L*s}=k*(\frac{mol}{L}) ^2\\\frac{mol}{L*s}=k*\frac{mol^2}{L^2}\\\\k=\frac{L^2*mol}{mol^2*L*s} \\\\k=\frac{L}{mol*s}

Which matches with C. L mol-1 s-1.

Best regards.

5 0
4 years ago
What is the molarity of a solution made by dissolving 20.0 g of H3PO4 in 50.0 mL of solution
Rom4ik [11]
(20*1000)÷(molecular weight of H3po4*50)

8 0
3 years ago
To draw a Lewis structure, it is not necessary to know
Karolina [17]
This answer to this question is the. Type of atoms in the molecule
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3 years ago
Which one of these complementary base pairs can form three hydrogen bonds?
ValentinkaMS [17]

Answer:

Option D is the correct answer

Explanation:

There are three hydrogen bonds formed between Guanine and Cytosine base.  

The first hydrogen bond is formed between the oxygen atom on Carbon-6 (C-6) of guanine, and one of the hydrogen atoms attached to the Nitrogen atom (i.e the one of the hydrogen atoms in the amino group) on the Carbon-4 (C-4)of the cytosine base.  

The second hydrogen bond is formed between the hydrogen atom on Nitrogen-1 (N-1) of the guanine base and Nitrogen-3 (N-3) of the cytosine base.

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7 0
4 years ago
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