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ra1l [238]
4 years ago
13

After landing on a distant exoplanet as a member of the Space Force Spec Ops Team one of your first tasks is to measure the grav

ity on the surface of the planet. Your weight feels heavier than on Earth, but that might just be the 80 kg spacesuit you are wearing. You pull out a 45.93 gram golf ball and drop it from eye level while recording the time it takes to hit the ground. You record 0.44 seconds for it to hit the ground. You have previously measured your eye level height to be 146 cm in preparation of this task. Using this information calculate the gravity on this new planet.
Physics
1 answer:
oksian1 [2.3K]4 years ago
6 0

Answer:

The acceleration due to gravity of the planet is approximately 15.083 m/s²

Explanation:

The given information are;

The mass of the golf ball = 45.93 gram

The time it takes the golf ball to hit the ground 0.44 seconds

The height, s, from which the golf ball is dropped = 146 cm = 1.46 m  

The equation of motion for the golf ball can be expressed as follows;

s = u·t + 1/2·a·t²

Where;

s = 1.46 m

u = The initial velocity of the golf ball = 0 m/s

a = The acceleration due to gravity of the planet

t = The time it takes the golf ball to hit the ground = 0.44 seconds

By substituting, we have;

1.46 = 0 × 0.44 + 1/2 × a × 0.44²

a = 1.46/(1/2 × 0.44²) ≈ 15.083 m/s²

The acceleration due to gravity of the planet = a ≈ 15.083 m/s².

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he deflection plates in an oscilloscope are 10 cm by 2 cm with a gap distance of 1 mm. A 100 volt potential difference is sudden
Lubov Fominskaja [6]

Answer:

Incomplete question

This is the complete question

The deflection plates in an oscilloscope are 10 cm by 2 cm with a gap distance of 1 mm. A 100 V potential difference is suddenly applied to the initially uncharged plates through a 1000 Ω resistor in series with the deflection plates. How long does it take for the potential difference between the deflection plates to reach 95 V?

Explanation:

Given that,

The dimension of 10cm by 2cm

0.1m by 0.02m

Then, the area is Lenght × breadth

Area=0.1×0.02=0.002m²

The distance between the plate is d=1mm=0.001m

Then,

The capacitance of a capacitor is given as

C=εoA/d

Where

εo is constant and has a value of

εo= 8.854 × 10−12 C²/Nm²

C= 8.854E-12×0.002/0.001

C=17.7×10^-12

C=17.7 pF

Value of resistor resistance is 1000ohms

Voltage applied is V = 100V

This Is a series resistor and capacitor (RC ) circuit

In an RC circuit, voltage is given as

Charging system

V=Vo[1 - exp(-t/RC)]

At, t=0, V=100V

Therefore, Vo=100V

We want to know the time, the voltage will deflect 95V.

Then applying our parameters

V=Vo[1 - exp(-t/RC)]

95=100[1-exp(-t/1000×17.7×10^-12)]

95/100=1-exp(-t/17.7×10^-9)

0.95=1-exp(-t/17.7×10^-9)

0.95 - 1 = -exp(-t/17.7×10^-9)

-0.05=-exp(-t/17.7×10^-9)

Divide both side by -1

0.05=exp(-t/17.7×10^-9)

Take In of both sides

In(0.05)=-t/17.7×10^-9

-2.996=-t/17.7×10^-9

-2.996×17.7×10^-9=-t

-t=-53.02×10^-9

Divide both side by -1

t= 53.02×10^-9s

t=53.02 ns

The time to deflect 95V is 53.02nanoseconds

5 0
3 years ago
In Newton's cannonball experiment, if the velocity is equal the orbital velocity the Cannon ball
Makovka662 [10]

In Newton's cannonball experiment, if the velocity is equal to the orbital velocity then the cannonball will stay in Orbit.

Newtons cannonball experiment stated that the distance that a cannonball will travel, before being drawn into the Earth by the forces of gravity, is dependent on the initial velocity.

Therefore, if the cannonball is launched at a velocity that matches the orbital velocity, then it will not be able to be drawn in by gravity due to the Earth moving away from the cannonball at the same speed at which the cannonball itself is falling.

This means that the cannonball will continue to fall without reaching the Earth, therefore staying in orbit, much like that of the moon or planets around the sun.

To learn more visit:

brainly.com/question/22360485?referrer=searchResults

5 0
3 years ago
The AM radio station WDRJ broadcasts news and sports at a frequency of 704 kHz (kilohertz). What is the wavelength of the radio
Doss [256]

Answer:

AM broadcasts occur on North American airwaves in the medium wave frequency range of 525 to 1705 kHz (known as the “standard broadcast band”). The band was expanded in the 1990s by adding nine channels from 1605 to 1705 kHz.

7 0
3 years ago
A car was traveling at 20m/s and slammed on the brakes causing the car to decelerate at a rate of -2.5 m/s^2 before coming to a
Taya2010 [7]

Answer: 160 m

Explanation: First find time or t using the formula for acceleration:

a = vf - vi / t

So t is equal to:

t = vf - vi / a

= 0 m/s - 20 m/s / -2.5 m/s²

= 8 s

To find the distance use the formula for velocity:

v = d / t

Derive for d:

d = v x t

= 20 m/s x 8 s

= 160 m

5 0
3 years ago
Anwser , this picture
Alisiya [41]
Can you answer more than once ? If so, it’s AB, CD, GH.
If not then CD
5 0
3 years ago
Read 2 more answers
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